How Do You Estimate Logarithms Using Basic Logarithmic Properties?

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SUMMARY

This discussion focuses on estimating logarithmic values using basic logarithmic properties. Participants utilized known values such as log(2) ≈ 0.30 and log(∏) ≈ 0.5 to derive log(4), log(5), log(6), and log(8). The method of linear interpolation was suggested for estimating log(5), calculated as log(5) ≈ (1/2)(log(4) + log(6)). Additionally, the relationship log(5) = log(10) - log(2) was confirmed, yielding log(5) ≈ 0.7.

PREREQUISITES
  • Understanding of basic logarithmic properties: log(ab) = log(a) + log(b), log(a/b) = log(a) - log(b), log(a^n) = nlog(a)
  • Familiarity with logarithmic values of common numbers, specifically log(2) and log(∏)
  • Basic knowledge of linear interpolation techniques
  • Ability to manipulate logarithmic equations for estimation
NEXT STEPS
  • Study the application of logarithmic properties in complex equations
  • Explore advanced interpolation methods for estimating logarithmic values
  • Learn about the significance of log(10) in logarithmic calculations
  • Investigate the relationship between logarithms and exponential functions
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Students, educators, and anyone interested in enhancing their understanding of logarithmic estimation techniques and properties in mathematics.

k3r0
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Homework Statement


Given that log(2) is roughly 0.30 and log(∏) is roughly 0.5, estimate the values of log(4), log(5), log(6) and log(8).


Homework Equations


log(ab)=log(a)+log(b)
log(a/b)=log(a)-log(b)
log(a^n)=nlog(a)


The Attempt at a Solution


I found log(4) and log(8) using log(2)+log(2) [+log(2)], and i estimated log(6) using log(2)+log(∏), but i don't know how to get to log(5).
 
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hi k3r0! :smile:

hint: log(125) ? :wink:
 
My guess, assuming there isn't a mistake in the problem statement, is that they want you to use linear interpolation. log(5) ≈ (1/2)(log(4) + log(6)). This would be the average (or mean) of the two log values.
 
Mark44 said:
My guess, assuming there isn't a mistake in the problem statement, is that they want you to use linear interpolation. log(5) ≈ (1/2)(log(4) + log(6)). This would be the average (or mean) of the two log values.

Thanks a lot, that method never crossed my mind. I spent about half an hour being irritated at that question, haha.

Thanks!
 
another hint: what is \pi^2 equal to?
 
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log(5)=log(10)-log(2) = 1 - log(2) = 0.7
 

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