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That depends what the answer in back of your book is.
Remember that you need the integral of 3(4-x2)1/2, not just (4-x2)1/2
The problem involves evaluating the integral ∫ from -2 to 2 of (x + 3)(4 - x^2)^(1/2) dx, with a focus on interpreting one part of the integral in terms of geometric area. The subject area pertains to integral calculus and geometric interpretation of integrals.
The discussion is ongoing, with various interpretations of the geometric figure involved. Some participants have provided guidance on how to approach the integral, while others express confusion about the area and the implications of the (x + 3) term. There is no explicit consensus on the shape or the area interpretation yet.
Participants are grappling with the geometric interpretation of the integral and the implications of the area under the curve. There are references to the area of a circle and the need to consider the entire integral rather than just parts of it. Some participants have noted the potential for confusion due to the answer provided in the textbook.
The question asked to interpret it in terms of area, that's why I didnt use any integration technique e.g. substitution, but instead tried to calculate in terms of half a circle (1/2 * pi * r^2). So is the answer at the back of my book wrong?
rock.freak667 said:\int_{-2} ^{2} (x + 3)(4 - x^2)^{\frac{1}{2}} dx
Try expanding out (x+3)(4-x2)1/2, then split the integral.
(Hint: (a+b)c = ac+bc)