That depends what the answer in back of your book is.
Remember that you need the integral of 3(4-x2)1/2, not just (4-x2)1/2
The question asked to interpret it in terms of area, that's why I didnt use any integration technique e.g. substitution, but instead tried to calculate in terms of half a circle (1/2 * pi * r^2). So is the answer at the back of my book wrong?
rock.freak667 said:[tex]\int_{-2} ^{2} (x + 3)(4 - x^2)^{\frac{1}{2}} dx[/tex]
Try expanding out (x+3)(4-x2)1/2, then split the integral.
(Hint: (a+b)c = ac+bc)