How Do You Find Absolute Extrema of a Polynomial Function?

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Homework Help Overview

The discussion revolves around finding the absolute maximum and minimum values of a polynomial function, specifically f(x) = 3x^4 - 8x^3 + 12x^2 - 48x + 25, within the interval [0, 3].

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to differentiate the function and is uncertain about how to handle a specific factor in the derivative. Participants question the relevance of certain steps and the existence of real solutions for a derived equation.

Discussion Status

Participants are engaging with the problem, offering feedback on the original poster's approach and raising questions about the implications of the derivative's factors. There is an acknowledgment of the need to consider both critical points and endpoints for determining extrema.

Contextual Notes

There is a mention of a specific interval for the problem, and some participants note potential errors in the original poster's calculations, suggesting a need for careful verification of the derivative's factors.

chaosblack
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simple SIMPLE local extremia question

Homework Statement



Find the absolute maximum and absolute minimum values of f(x) = 3x^4 - 8x ^3 + 12x^2 -48x +25, where 0 <= x <= 3.


Homework Equations



N/a

The Attempt at a Solution



f'(x) = 12x^3 - 24x^2 + 24x -48
= 12 (x^3 - 2x^2 + 2x -4)
= 12 (x-2) (X^2 +2)

I know how to do the rest, but just wondering before I go on... What should i do with that one factor...do I omit the (x^2 +2)?
 
Last edited:
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Well beside your first three lines of solution being irrelevant, it looks correct to me.

Edit: Actually you forgot a factor of 2 in your final h solution according to the symbolic result you derived earlier on.
 
Okay thanks a lot, I updated the thread with a different question lol
 
Well you know that the absolute maximum/minimum lies at a place where the derivative is 0 or at the endpoints of the interval. Does x^2+2=0 have a real solution?
 
haha...thanks man. I'm starting to forget to most simple stuff
 

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