How Do You Find the Angle of Incidence from a Prism to Air?

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Homework Help Overview

The discussion revolves around finding the angle of incidence from a prism to air, specifically in the context of light refraction through a prism. The original poster expresses confusion about the relationship between the angle of incidence and the angle of refraction, as well as the geometric principles involved.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods to determine the angle of incidence, including the use of triangles formed by the prism and light rays. Questions arise about the geometry involved, particularly regarding the angles at which normals meet and how to relate these to the angles of the prism.

Discussion Status

Participants are actively exploring different geometric approaches to the problem. Some have provided insights into the relationships between angles, while others are seeking clarification on specific geometric concepts. There is a sense of collaborative inquiry, with no explicit consensus yet reached.

Contextual Notes

There are indications of potential discrepancies in the problem statement and the values being used, which may affect the discussion. Additionally, participants are encouraged to apply their geometry skills to understand the relationships between angles better.

totomyl
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Homework Statement


it is the third question:
IMG_20161002_172724.jpg


Attempt

IMG_20161002_173241.jpg


Here is my attempt at the question, i got up to the point where i need to find the angle of incidence from the prism to the air, but i don't know how to do that. The solution page says to use 60o minus the angle of refraction i just calculated, but i don't know why we need to do that.

if you could please tell me why we use that or how we get the angle from the prism to the air, that would be very helpful. thank you.
 
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The statement of the problem does not match the numbers that you are using. Setting that aside, you can find the angle of incidence by bringing into the picture the upper triangle formed by the top apex of the prism, by the point where the ray enters the prism and the point where it exits the prism. You already know that one angle is 60o. You can relate the other two angles to the angle of refraction, which you already know, and the exit of angle that is the unknown.
 
An alternative method is to note that the two normals meet in the interior of the prism at an angle of 120°. Use the triangle Δabc formed by the normals and the light ray.

upload_2016-10-2_18-35-4.png
 
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gneill said:
An alternative method is to note that the two normals meet in the interior of the prism at an angle of 120°. Use the triangle Δabc formed by the normals and the light ray.

View attachment 106850
could i ask how you got the 120 when both of the normals meet? this is where my geometry skills come in i assume.
 
totomyl said:
could i ask how you got the 120 when both of the normals meet? this is where my geometry skills come in i assume.
Yes. It's just a matter of transferring angles around various reference lines and intersections. Erect a few verticals to create triangles and reference lines. Use the fact that triangle angles sum to 180 and complimentary angles to 90. See if you can't "transfer" the prism's base angles to where b is in the diagram (erect a vertical through b to divide the angle there into two parts). Give it a try.
 
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From geometry what is the sum of the interior angles of a 4-sided figure?
 
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gneill said:
Yes. It's just a matter of transferring angles around various reference lines and intersections. Erect a few verticals to create triangles and reference lines. Use the fact that triangle angles sum to 180 and complimentary angles to 90. See if you can't "transfer" the prism's base angles to where b is in the diagram (erect a vertical through b to divide the angle there into two parts). Give it a try.
i see, thank you for the help i think i can work out the rest on my own now. this was very helpful and will be useful for future reference.
 

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