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## Homework Statement

Red light is incident in air on a 30o - 60o - 90 o prism as shown. The incident beam is directed at an angle of φ1 = 44o with respect to the horizontal and enters the prism at a height h = 16 cm above the base. The beam leaves the prism to the air at a distance d = 41.5 along the base as shown.

What is φ3, the angle the transmitted beam makes with the horizontal axis?

http://imgur.com/poYBTbE

φ2 = 49.22 degrees

n2, index of refraction inside the prism = 1.47

## Homework Equations

Snell's Law: n1sinφ1 = n2sinφ2

angle geometry

## The Attempt at a Solution

I dropped a normal line between φ2 and φ3, so that I could find the angle of incident as α = 90-φ2 = 40.78. Then I used Snell's Law to calculate the angle of refraction β = 73.76 degrees. This angle is complementary to φ3, so 90 - β =16.24. For some reason this isn't the answer, though everything I know tells me it should be.

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