How do you find the direction of a vector given its magnitude and angle?

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SUMMARY

The discussion focuses on solving for the magnitudes of vectors A and B given the equation Vector A + Vector B + Vector C = 0. Vector A is directed negatively along the x-axis, Vector B is at an angle of 33.0 degrees above the positive x-axis, and Vector C has a magnitude of 13 m directed 37.0 degrees below the positive x-axis. The solution involves constructing a vector diagram and setting up equations based on the horizontal and vertical components of the vectors to find the unknown magnitudes of A and B.

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Homework Statement



Vector A points in the negative x direction. Vector B points at an angle of 33.0 degrees above the positive x axis. Vector C has a magnitude of 13 m and points in a direction 37.0 degrees below the positive x axis.

Given that , Vector A + Vector B + Vector C = 0, find the magnitudes of Vector A and Vector B.

Homework Equations





The Attempt at a Solution

 
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Construct a vector diagram. You should get a closed triangular loop from the three vectors.
 
egadda2 said:

Homework Statement



Vector A points in the negative x direction. Vector B points at an angle of 33.0 degrees above the positive x axis. Vector C has a magnitude of 13 m and points in a direction 37.0 degrees below the positive x axis.

Given that , Vector A + Vector B + Vector C = 0, find the magnitudes of Vector A and Vector B.

Homework Equations





The Attempt at a Solution

Let a = the magnitude of A = |A|
Let b = |B|
Let c = |C| = 13 (given)

Write the three vectors in terms of their coordinates, like this:
A = -a*i + 0*j
B = b*cos(33 deg)*i + b*sin(33 deg)*j
C = 13*cos (-37 deg)*i + 13*sin(-37 deg)*j

For the three vectors to sum to zero, their horizontal components have to add to zero, and their vertical components have to add to zero. Set up these two equations and solve for the unknowns a and b. Once you have these values you can find the magnitudes of A and B.
 

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