How Do You Find the Equation of a Plane Equidistant from Two Points?

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To find the equation of a plane equidistant from two points A=(2,0,2) and B=(4,2,0), it's essential to understand that the plane does not contain the points but is defined by their equidistance from all points on the plane. The directional vector AB can be used to determine a point on the plane, calculated as A + 0.5AB, resulting in the point (3,1,1). The equation of the plane can then be derived using the normal vector from the line connecting A and B, leading to the final equation x + y + z - 3 = 0. This approach clarifies the relationship between the points and the plane's orientation.
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Homework Statement


A plane lies inbetween two points A=(2,0,2) and B=(4,2,0). Let a point P=(x,y,z) be equally far away from A as from B.

Find the equation for this plane (like in this format: [PLAIN]http://upload.wikimedia.org/math/6/7/8/67834a730a04bb1f3d6ceab80f5284e4.png )

The Attempt at a Solution


Well.. What can I say. I basically got two points and I'm supposed to make a plane out of it (lmao), with no directional vectors or anything.

I also thought that a plane was infinitely big so I don't understand how a plane can be inbetween two points as explained in the assignment... The plane contains the two points is more correct to say, right?

Anyway can't you make an infinite number of planes with the given information? While a plane's equation (like this: [PLAIN]http://upload.wikimedia.org/math/6/7/8/67834a730a04bb1f3d6ceab80f5284e4.png ) describes one specific plane with a specific starting point and orientation?
 
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Nikitin said:

Homework Statement


A plane lies inbetween two points A=(2,0,2) and B=(4,2,0). Let a point P=(x,y,z) be equally far away from A as from B.

Find the equation for this plane (like in this format: [PLAIN]http://upload.wikimedia.org/math/6/7/8/67834a730a04bb1f3d6ceab80f5284e4.png )

The Attempt at a Solution


Well.. What can I say. I basically got two points and I'm supposed to make a plane out of it (lmao), with no directional vectors or anything.

I also thought that a plane was infinitely big so I don't understand how a plane can be inbetween two points as explained in the assignment... The plane contains the two points is more correct to say, right?

Anyway can't you make an infinite number of planes with the given information? While a plane's equation (like this: [PLAIN]http://upload.wikimedia.org/math/6/7/8/67834a730a04bb1f3d6ceab80f5284e4.png ) describes one specific plane with a specific starting point and orientation?
Yes you can make a single plane with this information. No, the plane does not contain the two points. The key point to note is that the two points are equidistant from all points on the plane.

To help you visualize this, consider a table top. Place one golf ball a distance 'd' above the table and a second ball a distance 'd' underneath the table, directly below the first. The two golf balls are your points and the table is your plane. Notice that if you tilt the table, but leave the golf balls in the same position, they will no longer be equidistant form all points on the plane. This is the key point. The two points are equidistant from all points on the plane.

Now, returning to your problem. Can you link the line joining the two points to the normal of the plane?
 
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OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOH! Now I get it

I thought the points were inbetween the plane as, in, like the golfballs were at two sides of the tabletop.

The directional vector would be AB. Wouldn't a point on the plane thus be A+0,5AB = (2,0,2)+0,5[2,2,-2]=(2,0,2) + [1,1,-1]=[3,1,1]

Then the equation 4 this stuff would simply be [2,2,-2]*[X-3,Y-1,Z-1]=
2x-6+2Y-2-2z+2 = 2x+2y+2z-6 = 0 ==> x+y+z-3=0

thanks 4 the help :)
 
Nikitin said:
OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOH! Now I get it

I thought the points were inbetween the plane as, in, like the golfballs were at two sides of the tabletop.

The directional vector would be AB. Wouldn't a point on the plane thus be A+0,5AB = (2,0,2)+0,5[2,2,-2]=(2,0,2) + [1,1,-1]=[3,1,1]

Then the equation 4 this stuff would simply be [2,2,-2]*[X-3,Y-1,Z-1]=
2x-6+2Y-2-2z+2 = 2x+2y+2z-6 = 0 ==> x+y+z-3=0

thanks 4 the help :)
Looks good to me :approve:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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