- #1

LD745

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- 0

How do you find the equations of the tangents to the graph of y=4x^3 that have slope 3?

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- Thread starter LD745
- Start date

- #1

LD745

- 2

- 0

How do you find the equations of the tangents to the graph of y=4x^3 that have slope 3?

- #2

Hurkyl

Staff Emeritus

Science Advisor

Gold Member

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It seems to me there are two obvious things to try:

- Find the points where the slope of the tangent would be 3, then find the lines
- Find the equations for
tangent lines, set the slope to 3, and solve**all**

(It's also against site policy to help people who just post their homework question and don't show any effort of their own...)

- #3

LD745

- 2

- 0

Oh i have...i found the derivative of 4x^3 which is 12x^2. and i also know that the point-slope formula has to be used.

- #4

mjpam

- 79

- 0

So, in the language of calculus, you have:

[itex]y-y_{1}=\frac{dy}{dx}(x-x_1)[/itex]

[itex]\{x\in \mathbb{R} :4x^{2}=0\}[/itex]

Do you see how you might solve the problem?

- #5

HallsofIvy

Science Advisor

Homework Helper

- 43,021

- 970

Since this has nothing to do with differential equations, I am moving it to Calculus and Beyond Homework.

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