- #1

- 2

- 0

How do you find the equations of the tangents to the graph of y=4x^3 that have slope 3?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter LD745
- Start date

- #1

- 2

- 0

How do you find the equations of the tangents to the graph of y=4x^3 that have slope 3?

- #2

Hurkyl

Staff Emeritus

Science Advisor

Gold Member

- 14,916

- 19

It seems to me there are two obvious things to try:

- Find the points where the slope of the tangent would be 3, then find the lines
- Find the equations for
tangent lines, set the slope to 3, and solve**all**

(It's also against site policy to help people who just post their homework question and don't show any effort of their own...)

- #3

- 2

- 0

Oh i have...i found the derivative of 4x^3 which is 12x^2. and i also know that the point-slope formula has to be used.

- #4

- 76

- 0

So, in the language of calculus, you have:

[itex]y-y_{1}=\frac{dy}{dx}(x-x_1)[/itex]

[itex]\{x\in \mathbb{R} :4x^{2}=0\}[/itex]

Do you see how you might solve the problem?

- #5

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

Since this has nothing to do with differential equations, I am moving it to Calculus and Beyond Homework.

Share:

- Replies
- 32

- Views
- 3K