How Do You Find the Momentum of a 1D Harmonic Oscillator?

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SUMMARY

The discussion focuses on calculating the momentum of a one-dimensional harmonic oscillator using its ground state wave-function, defined as $$\psi(x) = \sqrt\frac{a}{\sqrt\pi} * exp(-\frac{a^2*x^2}{2}\frac{i\omega t}{2})$$. Key formulas include the average potential energy $$\overline{V} = \frac{1}{2} \mu\omega^2\overline{x^2}$$ and average kinetic energy $$\overline{T} = \frac {\overline{p^2}}{2\mu}$$. The momentum probability function was also discussed, with the potential energy calculated as $$V=\frac{1}{4}\hbar\omega$$. The user seeks guidance on determining momentum from these calculations.

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ambroochi
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The ground state wave-function of a 1-D harmonic oscillator is
$$
\psi(x) = \sqrt\frac{a}{\sqrt\pi} * exp(-\frac{a^2*x^2}{2}\frac{i\omega t}{2}).
$$
a) find Average potential energy ?
$$
\overline{V} = \frac{1}{2} \mu\omega^2\overline{x^2}
$$
b) find Average kinetic energy ?
$$
\overline{T} = \frac {\overline{p^2}}{2\mu}
$$

c) find momentum probability function ?

solving for a i got the answer as
$$
V=\frac{1}{4}\hbar\omega
$$

how do i find the momentum here ?
 
Last edited:
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Hello Ambroochi. Welcome to PF :smile: !

That is all very nice, but what is your question ? And oh, perhaps you want to read the PF guidelines first. You will get much better assistance when you adhere to them !
 

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