How do you get a matrix from this basis?

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bartersnarter
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Homework Statement


Here's my problem. I only need help with the bottom part, but if you could explain the problem more vividly that would help too.
Kwvdeca.png

Homework Equations


A = S-1BS (?)
There aren't really any relevant equations. This part of linear algebra is getting really abstract, at least I think so. If there are any equations, I'm not aware of them.

The Attempt at a Solution


The problem I'm assigned for homework is very similar to this. I'm almost sure I got the answer right, but I don't completely understand the question. Why does the basis give that specific matrix B? What do you do with the basis to get B?
 
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Hello BS, welcome to PF :smile: !

Your hitting an extremely important subject in physics, math, engineering and what have you here !

Unfortunately, the explanation given in your text is already quite clear, so I find it difficult to add to it meaningfully.

Do you have any problem with the interpretation of matrix B on the basis of ##\mathfrak {B}## ?

How do you write vectors that are written as ##(\lambda, \mu)## on the basis of ##\mathfrak {B}## if you have to write them on the usual basis on ##\Re^2## ?

And if you apply the transformation B to ##(\lambda, \mu)## what do you get? And how does it look in ##\Re^2## ?

The other way around: what do you do to find the ##(\lambda, \mu)## corresponding to a vector ##(x, y)## in ##\Re^2## ?

---
Sorry about the ##\Re##, looks awful. Someone will know which fonts are available here, but I have trouble finding out

[edit] ah, found \mathbb : ##\mathbb R##
--​
 
Last edited:
Perhaps I can save a few words with a picture:

VecTransf.jpg

T is reflection about the line spanned by (2,3).
What is T of vector ##\vec v = (5,2)## ?

We found that T is diagonal on a basis ##\mathfrak B## consisting of ##\vec e_1 = (2,3)## and ##\vec e_2 = (-3,2)##
with ##T(\vec e_1) = (1) \vec e_1## and ##T(\vec e_2) = (-1) \vec e_1##
T is linear, which means that
the projection ##\lambda \vec e_1## of ##\vec v## on ##\vec e_1##
transforms into ##\lambda T(\vec e_1) = \lambda \vec e_1##

and the projection ##\mu \vec e_2## of ##\vec v## on ##\vec e_2##
transforms into ##\mu T(\vec e_2) = - \mu \vec e_2##
 
bartersnarter said:

Homework Equations


A = S-1BS (?)
There aren't really any relevant equations. This part of linear algebra is getting really abstract, at least I think so. If there are any equations, I'm not aware of them.
The formula for the ##\mathfrak B##-matrix of ##T## (for arbitrary ##\mathfrak B##) is certainly relevant.