How do you integrate around each singularity separately in complex analysis?

1 reply · 2K views · last reply
stripes
Messages
262
Reaction score
0

Homework Statement



Typeset problem: Prove (1/(2πi)) times the contour integral over C of e^(zt)/(z^2+1) dz equals sin t, where t>0 and C is |z|=3. Asks to do it two ways: (i) partial fractions of 1/(z^2+1), (ii) integrating around each singularity separately.


Homework Equations





The Attempt at a Solution



I did (i) by breaking the integrand into partial fractions and then using the Cauchy Integral Formula for each integral. I got the correct answer.

What does (ii) even mean? WHat does it mean to integrate "around each singularity separately"? The singularities are i and -i but I figure the only way to do this is partial fractions. Any help would be great.
 
Attachments
  • Typeset exercise: prove that (1/(2πi)) times the contour integral over C of e^(zt)/(z^2+1) dz equals sin t, where t > 0 and C is |z| = 3, then do it two ways: using partial fraction decomposition of 1/(z^2+1), and by integrating around each singularity separately.
    question.jpg
    10.3 KB · Views: 437
Alright, I got it. In case anyone ever comes across this:

All I did was break it down into two smaller contours, each one containing one of the singularities but not the other. Then the integral over the entire C is equal to the sum of two integrals; one over C1 (containing one singularity) and the other over C2 (containing the other singularity). Each integrand is the same, but you're just taking one integral over C1, plus the other integral over C2. Then apply the Cauchy integral formula to each integral and you end up with the exponential form of sin(t).