How Do You Integrate the Unit Step Function?

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SUMMARY

The discussion focuses on integrating the unit step function, specifically the integral of \(5u(t-1)\) from \(T\) to \(-T\). The user expresses confusion regarding the limits of integration and the behavior of the unit step function \(u(t)\) in the context of their professor's example. It is clarified that the limits of integration change due to the properties of the unit step function, which is zero for negative arguments. The user seeks clarity on how to properly set the limits when integrating functions involving shifted unit step functions.

PREREQUISITES
  • Understanding of the unit step function \(u(t)\)
  • Basic knowledge of integral calculus
  • Familiarity with limits of integration in definite integrals
  • Concept of piecewise functions in mathematical analysis
NEXT STEPS
  • Study the properties of the unit step function \(u(t)\) and its shifts
  • Learn how to evaluate integrals involving piecewise functions
  • Explore the concept of the Heaviside function in signal processing
  • Practice solving integrals with varying limits based on function behavior
USEFUL FOR

Electrical engineering students, signal processing practitioners, and anyone studying integral calculus involving piecewise functions will benefit from this discussion.

tdoc993
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This isn't really so much of a specific example from a textbook, I just need to understand how to do this kind of integral and from that I can infer how to do all of the other problems.

1. Homework Statement

The current problem I'm having trouble with is:

Integral of (5u(t-1)) from T to -T

Homework Equations


u(t) = { 0 t < 0
{ 1 0 < t

The Attempt at a Solution


My professor (who isn't the most clear professor in the world), has provided an example of a problem similar to this which is contradicting what I have found on the internet.

Basically what he has done is taken the integral of (A^2)u(t) dt from T to -T He skips right from the above equation directly to: Integral of A^2 dt from T to 0.

The problem I'm having is what happens to the u(t)? How does it simply disappear from his solution and how does that change the limits of integration? I know that in the unit step function there cannot be any negative numbers, so is that why he takes away the -T from the limits of integration?

Also for my problem, Integral of u(t-1), would that mean instead of the limits of integration changing to T to 0 would it be from T to 1 instead (because of the t-1). I'm really confused by this, and to add to the confusion everything I've found on the internet has told me that the integral of u(t) is tu(t). If anyone can clear this up for me I would very much appreciate it.

The course is Signals and systems I if anyone is wondering, it's part of an Electrical Engineering major, thanks in advance for any help.
 
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It might be helpful to draw a graph of what u(t-1) looks like. Then draw a graph of what 5u(t-1) looks like. You are going to be finding the integral under the plot from t=T to t=-T.

Chet
 

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