How Do You Integrate Cosine Powers in Calculus?

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golanor
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Homework Statement



[itex]\int { { cos }^{ 2n+1 }(x)dx }[/itex]

Homework Equations


[itex]{ cos }^{ 2 }+{ sin }^{ 2 } = 1[/itex]

The Attempt at a Solution


i got to here:
[itex]\int { { (1-{ sin }^{ 2 }(x)) }^{ n }d(sin(x)) }[/itex]

Any help would be appreciated!
 
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golanor said:

Homework Statement



[itex]\int { { cos }^{ 2n+1 }(x)dx }[/itex]

Homework Equations


[itex]{ cos }^{ 2 }+{ sin }^{ 2 } = 1[/itex]

The Attempt at a Solution


i got to here:
[itex]\int { { (1-{ sin }^{ 2 }(x)) }^{ n }d(sin(x)) }[/itex]

Any help would be appreciated!

There is no simple formula for the result, unless you want to express it in terms of a hypergeometric function. The answer is a polynomial of degree (2n+1) in ##\sin(x)##.

BTW: in [t e x] you should write "\sin(x)" instead of "sin(x)": the difference is ##\sin(x)## (nice) vs. ##sin(x)## (not nice).
 
Ray Vickson said:
There is no simple formula for the result, unless you want to express it in terms of a hypergeometric function. The answer is a polynomial of degree (2n+1) in ##\sin(x)##.

BTW: in [t e x] you should write "\sin(x)" instead of "sin(x)": the difference is ##\sin(x)## (nice) vs. ##sin(x)## (not nice).
Thanks for the tex hint..still getting the hang of it (used to microsoft equation editor =\)

micromass said:
So you got to find

[tex]\int (1-x^2)^ndx.[/tex]

Use the binomial theorem and linearity of the integral.
Thanks, i actually read about it, thought that i should use it but decided not to.

In case anyone wants the answer, it is:
[tex]\int { { (1-{ \sin }^{ 2 }(x)) }^{ n }d(\sin (x)) } =\sin (x)-\frac { n{ \sin }^{ 3 }(x) }{ 3 } +...+\frac { { (-1) }^{ n }{ \sin }^{ 2n+1 }(x) }{ 2n+1 } +C[/tex]