If dy/dx = cosx sin(adsbygoogle = window.adsbygoogle || []).push({}); ^{2}x and if y = 1 when x = pi/2, what is the value of y when x = 0?

So, i separate the derivative into dy = cosx sin^{2}x dx

Then integrate both sides...this is where i'm stuck.

How do you integrate cosx sin^{2}x? I've tried u-sub and IBP but failed both times!

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# Homework Help: How do you integrate cosx sin2x?

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