How Do You Integrate -e^(-|x|) Over All Real Numbers?

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SUMMARY

The integral of the function -e^(-|x|) over all real numbers evaluates to -2. The solution involves splitting the integral into two parts: from negative infinity to 0 and from 0 to positive infinity. By recognizing that |x| equals -x for x < 0 and |x| equals x for x > 0, the integrals can be computed separately. The integral from 0 to infinity yields -1, while the integral from negative infinity to 0 yields 1, resulting in a total of -2.

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1. Homework Statement and equations
Find \int -1e-|x| between negative infinity and positive infinity.

2. The attempt at a solution

So I tried to just integrate using laws for logarithmic equations and got:
e-|x| between negative infinity and positive infinity.
Of course this leaves me with:
e-∞-e-∞ = 0
I know the answer is -2, but I am not sure how to get there. Help would be much appreciated.
 
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Try splitting the integral into two separate integrals over two separate domains.

Use the fact that |x| = -x when x<0 and |x|=x for x>0.
 
Thanks danago, I think i figured it out. I split the integral and added the integral of the function from 0 to infinity with -infinity to 0. The first one came out to -1 and the next came out to 1 respectively, giving me -2. I fail to see how I should have caught this before though since the function is defined at 0. I guess you could see that is symmetric and just double the integral from 0 to infinity?
 

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