How Do You Isolate dS in the Equation dS(27.0m/s) = (dS + 30.0m)(9.0m/s)?

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The equation dS(27.0m/s) = (dS + 30.0m)(9.0m/s) is solved to isolate dS, resulting in a value of 15 meters. The process involves rearranging the equation to bring all terms involving dS to one side, leading to the equation 27dS = 9dS + 270. Simplifying this yields 18dS = 270, and dividing both sides by 18 gives dS = 15m. This method effectively demonstrates algebraic manipulation to isolate variables in physics equations.

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solve for dS(distance for Seth)

dS(27.0m/s) = (dS + 30.0m)(9.0m/s)

dS = 15m

how do you get dS on 1 side?
 
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dS(27.0m/s) = (dS + 30.0m)(9.0m/s)
27ds=9ds+270
18ds=270
ds=270/18
ds=15

Good luck
 

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