How do you prove the commutative property of multiplication for 4+ factors?

  1. I don't know how to construct formal proofs but there is the obvious geometric approach for 2 and 3 factors. However, how do you prove the commutative property holds up for 4+ factors? You end up with a lot of different orders in which you can multiply the factors and you can't just construct a geometric object from them.
     
    Last edited: May 23, 2011
  2. jcsd
  3. Mark44

    Staff: Mentor

    I don't see where geometry comes into it.
    The commutative property of multiplication says that ab = ba. For 3 factors it would be abc = cba. For four factors, I guess you're trying to prove that abcd = dcba.
    abcd = (ba)(dc) = (dc)(ba) = dcba
     
  4. Ya after I posted this and hopped on the bus I realized it was a retarded question lol. Thanks for the response though man.
     
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