- #1

- 5

- 0

displacement =(initial velocity)time+acceleration(time

^{2})/2

I've already tried it but can't. Please help me

Thanks.

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- Thread starter Archit
- Start date

- #1

- 5

- 0

displacement =(initial velocity)time+acceleration(time

I've already tried it but can't. Please help me

Thanks.

- #2

berkeman

Mentor

- 59,268

- 9,427

displacement =(initial velocity)time+acceleration(time^{2})/2

I've already tried it but can't. Please help me

Thanks.

Welcome to the PF.

Sure you can. The "a" in your first equation is the "acceleration" in your second equation.

- #3

- 5

- 0

That acceleration is from gravity and I want to know the force taken to throw an objectWelcome to the PF.

Sure you can. The "a" in your first equation is the "acceleration" in your second equation.

- #4

berkeman

Mentor

- 59,268

- 9,427

That acceleration is from gravity and I want to know the force taken to throw an object

So you write equations in both the x and y directions. Depending on the angle that the projectile is thrown, it may have both x and y components of acceleration that give the projectile initial velocity in the x and y directions. After that, only the acceleration of gravity affects the projectile in the y direction (assuming no air resistance effects).

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