How Do You Solve a Complex Contour Integral with a Non-Standard Path?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
dan280291
Messages
8
Reaction score
0
Hi I'm really not sure how to start this question. I could do it if it was in terms of z but I'm not sure if trying to change the variable using z = x + iy is correct. If anyone could suggest a method I'd appreciate it.

∫(x3 - iy2)dz

along the path z= [itex]\gamma(t)[/itex] = t + it3, 0≤t≤1

Thanks
 
Physics news on Phys.org
dan280291 said:
Hi I'm really not sure how to start this question. I could do it if it was in terms of z but I'm not sure if trying to change the variable using z = x + iy is correct. If anyone could suggest a method I'd appreciate it.

∫(x3 - iy2)dz

along the path z= [itex]\gamma(t)[/itex] = t + it3, 0≤t≤1

Thanks

I think it's safe to assume that [itex]z = x + iy[/itex] if nothing to the contrary is given.

You have [itex]z = \gamma(t)[/itex] so [itex]dz = \gamma'(t)\,dt[/itex] and [itex]x[/itex] and [itex]y[/itex] are respectively the real and imaginary parts of [itex]\gamma(t)[/itex].