How Do You Solve a Complex Epicyclic Gearbox Assignment?

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SUMMARY

The discussion focuses on solving a complex assignment related to epicyclic gearboxes in a mechanical engineering course. The main challenge is calculating the output speed to input speed ratio for a modified gearbox. Key concepts mentioned include the gear module formula (m = D/T) and the importance of consistent modules for meshing gears. The user previously calculated a 6:1 reduction ratio and a fixing torque of 25.46 Nm for a simpler question but struggles with the complexities of the new assignment.

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  • Understanding of epicyclic gearbox mechanics
  • Familiarity with gear module calculations (m = D/T)
  • Knowledge of speed and torque relationships in gear systems
  • Basic principles of mechanical engineering
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  • Research advanced epicyclic gearbox design principles
  • Study the calculation of output speed ratios in complex gear systems
  • Learn about torque transmission in planetary gear arrangements
  • Explore examples of modified gearbox configurations and their analyses
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Mechanical engineering students, educators teaching gear systems, and professionals involved in gearbox design and analysis.

dstealth
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Hi all, I'm Chris, a first time poster!

Currently stuck on an assignment question for my mechanical engineering course. The question is shown in the picture below. The capital T refers to 'teeth', as in 20T is 20 teeth on that particular gear. Ignore the little arrows with P and S - that is just me labeeling up the planetary and the sun gears. I answered a previous question on epicyclic gearboxes no problem but we have not been taught how to answer one this complex:-

Picture 002.jpg


Any pointers?

Thanks in advance.
 
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The question is essentially asking for the ratio of the output speed to the input speed.

If I remember correctly the module m= D/T and for meshing gears, the modules are the same.
 
rock.freak667 said:
The question is essentially asking for the ratio of the output speed to the input speed.

If I remember correctly the module m= D/T and for meshing gears, the modules are the same.

Shown in the pictures is the previous question which that question is based upon, along with my working out. I calculated a 6:1 reeduction ratio for the first question and a fixing torque of 25.46 Nm. I just don't know how to do the second question of the 'modified' gearbox that I posted in the first post.

Picture 003.jpg


Picture 004.jpg


Thanks
 
I'm sure the working out is simple, it's just we haven't covered any examples like this in the lesson.
 

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