How Do You Solve for c in a Normal Distribution Problem?

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SUMMARY

The discussion centers on solving for the variable c in a normal distribution problem where the mean is 3 and the variance is 16. The user attempts to express the probability P(|X-2|>c)=0.6 by manipulating the cumulative distribution function (CDF) of the normal distribution. The user correctly identifies the need to calculate probabilities using the standard normal distribution tables but encounters difficulty in interpreting the results. The conversation emphasizes the importance of showing initial attempts in problem-solving to facilitate better assistance.

PREREQUISITES
  • Understanding of normal distribution concepts, including mean and variance.
  • Familiarity with cumulative distribution functions (CDF) and probability calculations.
  • Experience with standard normal distribution tables.
  • Basic skills in algebraic manipulation of probability expressions.
NEXT STEPS
  • Study the properties of normal distribution, focusing on mean and variance calculations.
  • Learn how to use cumulative distribution functions (CDF) for normal distributions.
  • Practice solving probability problems involving absolute values in normal distributions.
  • Explore the use of statistical software tools like R or Python for normal distribution analysis.
USEFUL FOR

Students studying statistics, educators teaching probability theory, and anyone looking to deepen their understanding of normal distribution problems.

littlerich
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Normal Distribution: Mean = 3, Variance = 16

P(|X-2|>c)=0.6

Find c.

I'm so stuck...

Please Help Me

Rich
 
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First off, you should post homework in the homework forums.

Secondly, we're not here to do your homework for you. (See https://www.physicsforums.com/showthread.php?t=94383) You have to show us what you've tried on the problem, even if you think it is going nowhere! (e.g. it is almost always a good idea to try applying the definitions of things -- some of us get the feeling you haven't even bothered trying to do the problem if you haven't even done that!)

Finally, your post is a little confusing. I suppose you meant to say that X is a normally distributed random variable with mean 3 and variance 16?
 
Hey

Yea, that's what i meant...

What I've tried so far is:

P(X>c+2)+P(X<2-c)=0.6

Hence: P(X<c+2)-P(X<2-c)=0.4

And because my tables are backwards i changed it to:

P(X>2-c)-P(X>c+2)=0.4

0.4 then comes up as 0.2533 in the tables, and now I am stuck.
 

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