How Do You Solve for e11 and e12 When (e11)^2 + (e12)^2 = 1?

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Homework Help Overview

The discussion revolves around finding the values of e11 and e12 given the equation (e11)^2 + (e12)^2 = 1, which is related to eigenvectors of a specific matrix corresponding to an eigenvalue.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore how to derive e11 and e12 from the eigenvalue equation and question the specifics of the problem setup. Some suggest writing down the eigenvalue equation and manipulating it to find the unknowns.

Discussion Status

There is an ongoing exploration of the relationship between e11 and e12, with some participants providing guidance on how to approach the problem. Multiple interpretations of the problem are being discussed, particularly regarding the choice of values for e11 and e12.

Contextual Notes

Participants note the importance of the constraint that (e11)^2 + (e12)^2 = 1, which is relevant to ensuring the eigenvector has unit length. There is mention of the matrix and eigenvalue involved, but no resolution has been reached.

tuanle007
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can someone look at the image...
can someone teach me/ help me remember how we can get
e11 and e12
thank you so much
tuan
 
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here is the picture
 

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What is this; a homework question or what? I don't really understand what you want explaining to you. Is there a specific question that the attachment is a solution to?
 
You can get e11 and e12 as in the picture. Just write down the eigenvalue equation, multiply it out and solve the two given equations for the two unknowns. That's all that is happening. If you want more help, you need to be more specific.
 
Apparently this is to find eigenvectors of the matrix
[tex]\left(\begin{array}{cc} 3 & \sqrt{2} \\ \sqrt{2} & 4\end{array}\right)[/tex]
corresponding to eigenvalue 5.

Since you want, by definition of "eigenvalue" and "eigenvector"
[tex]\left(\begin{array}{cc} 3 & \sqrt{2} \\ \sqrt{2} & 4\end{array}\right)\left(\begin{array}{c}e_{11} \\ e_{12}\end{array}\right)= \left(\begin{array}{c} 5e_{11} \\ 5e_{12}\end{array}\right)[/tex]

Which leads to the equation in your post
[tex]\left(\begin{array}{cc}-2e_{11}+ \sqrt{2}e_{12}\\ \sqrt{2}e_{11}- e_{12}\end{array}\right)= \left(\begin{array}{c}0 \\ 0\end{array}\right)[/tex]

That gives you the two equations [itex]-2e_{11}+ \sqrt{2}e_{12}= 0[/itex] and [itex]\sqrt{2}e_{11}- e_{12}= 0[/itex]. Because 5 is an eigenvalue, if you try to solve those two simultaneous equations you will find they are "dependent"- they reduce to a single equation: [itex]\sqrt{2}e_{11}= e_{12}[/itex]. Choosing either of those to be any number you want, you can solve for the other. In your attachment, they choose [itex]e_{11}= 1[/itex] so [itex]e_{12}= \sqrt{2}[/itex]. Any eigenvector of the equation, corresponding to eigenvalue 5, is a multiple of [itex](1, \sqrt{2})[/itex].

The other eigenvalue, by the way, is 2. What are the eigenvectors corresponding to eigenvalue 2?
 
HallsofIvy said:
In your attachment, they choose [itex]e_{11}= 1[/itex] so [itex]e_{12}= \sqrt{2}[/itex]. Any eigenvector of the equation, corresponding to eigenvalue 5, is a multiple of [itex](1, \sqrt{2})[/itex].
Actually, they choose [itex]e_{11}, e_{12}[/itex] such that the eigenvector has unit length
[tex]|| (e_{11}, e_{12}) || = \sqrt{ e_{11}^2 + e_{12}^2 }[/tex]
 
i think compuchip is correct..
i found out how to do it yesterday..
u have to set (e11)^2 + (e12)^2 =1
and solve for e11, and e12...
 

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