How Do You Solve for 'v' in the Equation F = qE + qvB?

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SUMMARY

The equation F = qE + qvB can be rearranged to solve for 'v' effectively. The correct manipulation leads to the formula v = (F - qE) / (qB). This approach clarifies that 'v' is isolated by dividing both sides by 'qB', ensuring that 'q' and 'B' do not remain attached to 'v'. The final expression accurately reflects the relationship between force, electric field, and magnetic field in this context.

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  • Understanding of basic algebraic manipulation
  • Familiarity with the concepts of electric force (F), electric field (E), and magnetic field (B)
  • Knowledge of the variables involved in electromagnetic equations
  • Basic physics principles related to charged particles and forces
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Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify concepts related to force and motion of charged particles.

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Homework Statement


so, the question is basically asking me to rearrange F = qE + qvB to find 'v'.

The Attempt at a Solution


I'm not the greatest at rearrangements, but here is my attempt.

F - qvB = qE
F - v = qE / qB (q values cancel each other out)
v = (E / B) + F

is this right, or have i gone wrong somewhere?

Any help would be much appreciated :)
 
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Dark_Dragon said:

Homework Statement


so, the question is basically asking me to rearrange F = qE + qvB to find 'v'.

The Attempt at a Solution


I'm not the greatest at rearrangements, but here is my attempt.

F - qvB = qE
F - v = qE / qB (q values cancel each other out)
v = (E / B) + F

Let's make things simpler and write:

qvB=F-qE

you should understand this (we are making the term we want as the subject)

Since we don't want the 'q' and 'B' to be by the 'v', what happens if we divide both sides by 'qB'?
 
wouldn't you get:
v = (F - E) / B ?
 
Dark_Dragon said:
wouldn't you get:
v = (F - E) / B ?

There no 'qB' by the 'F', so the 'F' becomes 'F/qB'.
 

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