How Do You Solve for 'v' in the Equation F = qE + qvB?

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To solve for 'v' in the equation F = qE + qvB, the equation can be rearranged to isolate 'v'. Starting from F - qvB = qE, dividing both sides by qB leads to v = (F - qE) / qB. Simplifying further, the correct form for 'v' is v = (F - E) / B, assuming 'q' is constant and can be factored out. The discussion emphasizes the importance of correctly manipulating the equation to achieve the desired variable isolation. Understanding these algebraic steps is crucial for solving similar physics equations.
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Homework Statement


so, the question is basically asking me to rearrange F = qE + qvB to find 'v'.

The Attempt at a Solution


I'm not the greatest at rearrangements, but here is my attempt.

F - qvB = qE
F - v = qE / qB (q values cancel each other out)
v = (E / B) + F

is this right, or have i gone wrong somewhere?

Any help would be much appreciated :)
 
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Dark_Dragon said:

Homework Statement


so, the question is basically asking me to rearrange F = qE + qvB to find 'v'.

The Attempt at a Solution


I'm not the greatest at rearrangements, but here is my attempt.

F - qvB = qE
F - v = qE / qB (q values cancel each other out)
v = (E / B) + F

Let's make things simpler and write:

qvB=F-qE

you should understand this (we are making the term we want as the subject)

Since we don't want the 'q' and 'B' to be by the 'v', what happens if we divide both sides by 'qB'?
 
wouldn't you get:
v = (F - E) / B ?
 
Dark_Dragon said:
wouldn't you get:
v = (F - E) / B ?

There no 'qB' by the 'F', so the 'F' becomes 'F/qB'.
 
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