How Do You Solve Integral of e^(2y)sin(2y) dy Using Integration by Parts?

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SUMMARY

The integral of e^(2y)sin(2y) dy can be solved using the method of integration by parts. By applying the integration by parts formula, integral udv = uv - integral vdu, twice, the original integral reappears, allowing for a straightforward algebraic solution. This technique leads to a solvable equation where the integral can be isolated and solved directly. The final result is derived by recognizing the cyclical nature of the integrals involved.

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  • Understanding of integration by parts
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  • Knowledge of trigonometric integrals
  • Basic algebraic manipulation skills
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Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for effective methods to teach integration by parts.

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Homework Statement



Evaluate integral of e2ysin(2y)dy using integration by parts.

Homework Equations



integral udv = uv - integral vdu

The Attempt at a Solution



I tried applying the above equation several times, but the integral and derivative of both e2y and sin(2y) will always have a y in them.

Let me know if you have any ideas,

Thanks.
 
Last edited:
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Integrate by parts twice. Then you'll get back to your original integral and will be able to write it in terms of the uv terms you've accumulated.
 
once you integrate once you're going to get another integral (the integral vdu) which is going to be another integration by parts. . .do that again and the third integral will also be an integration by parts. . .but luckily enough it will be e^(2y) sin(2y)dy so then you have your equation

int{e^(2y) sin(2y)dy} = BLAH BLAH BLAH - int{e^(2y) sin(2y)dy}
so since you have the same thing on both sides of the equation you can just solve for it. . .
 

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