How Do You Solve Thevenin's Theorem Problems with Different Load Resistances?

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Discussion Overview

The discussion revolves around solving problems related to Thevenin's Theorem, specifically focusing on determining the current through a load resistor (RL), the voltage across RL, and the power developed in RL for various values of RL. The context includes homework help and practical application of Thevenin's Theorem in circuit analysis.

Discussion Character

  • Homework-related
  • Exploratory
  • Technical explanation

Main Points Raised

  • One participant expresses confusion about how to apply Thevenin's Theorem to a specific exam question involving different values of RL.
  • Another participant suggests that the problem involves converting the circuit into a Thevenin equivalent and performing analysis with the different RL values.
  • Some participants discuss the process of finding Thevenin voltage and resistance, emphasizing the importance of correctly identifying the terminals and circuit configuration.
  • There is mention of creating multiple Thevenin equivalents, with some participants questioning the necessity of this approach and suggesting a single equivalent circuit instead.
  • One participant expresses difficulty due to the complexity of the circuit compared to textbook examples, which typically feature simpler configurations.
  • Another participant provides guidance on calculating Thevenin voltage using the voltage divider rule and finding total resistance without RL present.
  • One participant reports calculating the Thevenin voltage and resistance and seeks clarification on how to incorporate RL back into the circuit for further analysis.
  • Finally, a participant describes their process of adding RL back into the circuit and calculating current, voltage, and power, while seeking validation of their method.

Areas of Agreement / Disagreement

Participants generally agree on the steps involved in applying Thevenin's Theorem, but there is some disagreement regarding the necessity of creating multiple equivalent circuits and the complexity of the problem. The discussion remains unresolved regarding the best approach to take for the specific problem at hand.

Contextual Notes

Some participants express uncertainty about their calculations and understanding of the circuit configuration, indicating potential limitations in their grasp of the material. There are also references to differing examples in textbooks that may not align with the current problem.

Who May Find This Useful

Students studying electrical engineering or related fields who are seeking assistance with Thevenin's Theorem and circuit analysis may find this discussion beneficial.

amy_a
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practice exam question HELP PLEASE!

hi guys, I've been going through my past exam papers and i found this question. my lecturer says that a similar question will be on my exam but i haven't got any idea how to do it :cry: can anybody help me please?

i have to determine the current through RL, the voltage across RL and the power developed in RL for the following values of RL using thevenins theorem.

(i) RL = 1 ohm
(ii) RL = 2.83 ohm
(iii) RL = 4 ohm


Im so confused!

can anyone give me some pointers... x
 

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i think it is just an exercise of turning your circuit about terminals AB into a thevenin equivalent, and then do a simple analysis on the remaining circuit with different values of RL. Clearly, you must first learn how to convert everything left of AB into its thevenin equivalent. once that's done the rest would be simple.
 
Yepp, mjsd is correct, leave the Rl alone and apply thevenin equivalent.
Find thevenin voltage across the OPEN circuit.
Replace batteries by short.
Find thevenin resistance... and so on.P.S I think this thread belongs in the homework-section.
 
Last edited:
antoker said:
P.S I think this thread belongs in the homework-section.

Yep, thread moved to Homework Help. Welcome to the PF, amy_a. It's a great place. Please keep in mind that homework and coursework questions must be posted in the appropriate Homework Help section, and not in the general forums. o:)
 
oops. I am sorry bout that. i didnt realize there was a coursework section. thanks for moving the thread:approve: thank u for the replies as well guys. i managed to make two thevenin equivalent circuits from terminals a and b and c and d. is that correct? i found the voltage values from this but I am still quite stuck on what to do next. how would i use the RL values and answer the question? i really am a dumb blonde i think!:smile:
 
amy_a said:
oops. I am sorry bout that. i didnt realize there was a coursework section. thanks for moving the thread:approve: thank u for the replies as well guys. i managed to make two thevenin equivalent circuits from terminals a and b and c and d. is that correct? i found the voltage values from this but I am still quite stuck on what to do next. how would i use the RL values and answer the question? i really am a dumb blonde i think!:smile:
Why are you getting two equivalents? ;) You're supposed to create a equivalent circuit between A-B terminals, so your circuit will be reduced to a single voltage source with a single series resistor, coupled toward Rl. After that finding voltage/current will be extremely easy. By simply using voltage divider rule ;) Or, you can do thevenin between C-D terminals and then apply loop equations to find the voltage across Rl.

P.S please post your thevenin circuit.
 
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hi, i tried to make an equivalent circuit but I am really quite useless at this. I've only just began studying this module! the problem is that my textbooks only have examples of thevenin circuits with one resistor parallel to the battery where as this question has 2. this is why I am confused! I am certain I've done this wrong so please don't laugh at my disastrous attempt at an equivalent circuit.:confused:
 

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amy_a said:
hi, i tried to make an equivalent circuit but I am really quite useless at this. I've only just began studying this module! the problem is that my textbooks only have examples of thevenin circuits with one resistor parallel to the battery where as this question has 2. this is why I am confused! I am certain I've done this wrong so please don't laugh at my disastrous attempt at an equivalent circuit.:confused:

Ok, I'll take a look as soon as the image gets approved :cool:

Update: ok, i can see it now, i'll take a look in an hour or so.
 
Last edited:
thanks antoker, i really appreciate your help. I am so useless at electrical engineering. its by far my weakest subject :rolleyes:
 
  • #10
amy_a: take a look at your first circuit. Remove the Rl, and compute the voltage across the 7Ohm resistance that is in parallel with Rl. That is your thevenin voltage(Hint: Use voltage divider equation, to obtain the voltage between C&D nodes). Then, replace your source battery by a short and compute total resistance, without the Rl present.
 
  • #11
hi antoker, thanks for all this help :smile: I've scribbled down what u told me and i found the thevenin voltage at terminals ab to be 9.94V. i then found the thevenin resistance to be 9.73 ohms. how would i go about adding RL back into the circuit so i can find the current across it etc?
 
  • #12
hey, i think i figured it out ( i hope) i used the thevenin circuit and added in the RL resistor. i then found the total resistance by addin them both together and then found the current V/total resistance. with the current i found the voltage across RL and finally the power developed across RL. is that the right method? i hope so!
 
  • #13
amy_a said:
hey, i think i figured it out ( i hope) i used the thevenin circuit and added in the RL resistor. i then found the total resistance by addin them both together and then found the current V/total resistance. with the current i found the voltage across RL and finally the power developed across RL. is that the right method? i hope so!

applause :smile:P.S. I have not checked your calculations, but it seems to be correct.
 

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