How Do You Solve Trigonometric Equations for Angles Between 0 and 180 Degrees?

  • Thread starter Thread starter babacanoosh
  • Start date Start date
Click For Summary
The discussion focuses on solving various trigonometric equations for angles between 0 and 180 degrees. Participants share methods for manipulating equations, using identities, and factoring to find solutions. Key equations discussed include sin2x = cos3x, 2cos^2x = sinx + 1, and tan^2x = 3tanx. The importance of correctly applying the quadratic formula and recognizing valid solutions within the specified range is emphasized. Overall, the conversation highlights collaborative problem-solving and the need for clarity in understanding trigonometric identities and algebraic manipulation.
  • #31
babacanoosh said:
ok thanks for your help,

tanx=0

x=180k degrees,
so the answer would be 360k degrees.
Yes, but don't forget your solutions are from 0-180.

tanx=0 whenever sinx=0.
 
Physics news on Phys.org
  • #32
ok, thanks
 
  • #33
i have a few new problems that i can't seem to get:

Solve 0-180 degrees

tan^2x- (square root of 3)tanx=0

Attempt:
simplified it all the way down to 1-ot^2x=sec^2x...stuck there, or i just did i way wrong

Next problem:

tan2xcotx-3=0

attempt:

simplified it to sinx=1/2...

i did it wrong, because this is the wrong answer.
 
  • #34
\tan^2 x -\sqrt 3 \tan x=0

Correct?
 
Last edited:
  • #35
sorry let me try again..


tan^2x - (square root of 3) *tanx=0
 
  • #36
What common term do you have that you could factor ... ? You explored this method with the other problems, refer back to them if you need.
 
  • #37
tangent...
tan(tan-square root of 3)=0
tan = 0

0 degrees and 180 degrees

tan = square root of 3

60 degrees,

so answer is 0, 60, 180 degrees

thanks, i don't understand why i didnt see that one, however the next one i am still stuck
 
  • #38
How did you simplify it to sinx=1/2?
 
  • #39
i don't even know anymore, it involved squaring the equation and then changing cot^2x into 1-csc^2x...im way off i guess.
 
  • #40
\tan 2x \cot x -3 =0

Use an identity to re-write tan2x then use another identity to get it in terms of x, not 2x, and change cotx in terms of sines and cosines. Cancel like terms and multiply like terms, and it's solved.
 
  • #41
ok thanks,

Another problem, same directions:

sin2x=2cosx

attempt:

2sinxcosx-2cosx=0
2sinx-cosx=0

stuck on what to do from here
 
  • #42
2sinxcosx-2cosx=0
2sinx-cosx=0

What was your reasoning for the 2nd step? Refer back to the 1st problem we worked on tonight ... I don't think you're thinking hard enough.
 
  • #43
I'm sorry, that's wrong,

well cos(2sin -2)=0
cos=0

90 degrees

sinx=1

90 degres

the final answer would be 90 degrees
 
  • #44
That's right.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
6K
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K