What Are the Solutions for cos(2x) + cos(x) = 0?

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Homework Help Overview

The discussion revolves around the equation cos(2x) + cos(x) = 0, with the domain specified as 0 <= x <= 360 degrees. Participants are exploring potential solutions and clarifying the notation used in the equation.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss various approaches to solving the equation, including attempts to factor and solve for x. There are questions about the correct interpretation of the notation (cos(2x) vs. cos2x) and whether all possible solutions have been identified. Some suggest specific values such as 60 degrees and 300 degrees, while others express uncertainty about additional solutions.

Discussion Status

The discussion is ongoing, with participants providing insights and suggestions. Some guidance has been offered regarding notation and potential solutions, but there is no explicit consensus on the completeness of the solutions presented.

Contextual Notes

Participants note the importance of clear notation to avoid confusion, especially for those new to writing mathematical expressions. There is also mention of constraints related to the specified domain of the problem.

Helly123
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Homework Statement


cos2x + cos x = 0 (0 <= x <= 360)

Homework Equations

The Attempt at a Solution


cos2x + cos x = 0
2cos(3x)/2 cos(x)/2 = 0

3x/2 = 90 degrees
x = 60 degrees

x/2 = 90
x = 180

3x/2 = 270
x = 180

x/2 = 270
x = 540 (not qualified)

is there any more possibility (answers) for x?
 
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Helly123 said:
cos2x + cos x = 0 (0 <= x <= 360)
Is it cos(2x) or cos2x?
 
cnh1995 said:
Is it cos(2x) or cos2x?
it's cos2x
 
Helly123 said:
it's cos2x
Of course:-p!
I hadn't read your complete solution.

But I think you've found all the possible values for x.
 
cnh1995 said:
Of course:-p!
I hadn't read your complete solution.

But I think you've found all the possible values for x.
thank you. But there's one more answers but I don't know how to find it
 
Check the 270...
 
BvU said:
Check the 270...
I see, I get it. thanks
 
Helly123 said:

Homework Statement


cos2x + cos x = 0 (0 <= x <= 360)

Homework Equations

The Attempt at a Solution


cos2x + cos x = 0
2cos(3x)/2 cos(x)/2 = 0

3x/2 = 90 degrees
x = 60 degrees

x/2 = 90
x = 180

3x/2 = 270
x = 180

x/2 = 270
x = 540 (not qualified)

is there any more possibility (answers) for x?
What about 300°?
 
Why didn't you just write $$\cos{2x}=2\cos^2{x}-1$$and then directly solve the resulting (factorable) quadratic equation for ##\cos{x}##
 
  • #10
ehild said:
What about 300°?
Yes, that's the answer
 
  • #11
Chestermiller said:
Why didn't you just write $$\cos{2x}=2\cos^2{x}-1$$and then directly solve the resulting (factorable) quadratic equation for ##\cos{x}##
I see.. I didn't realize it
 
  • #12
Helly123 said:
cos2x + cos x = 0 (0 <= x <= 360)

cnh1995 said:
Is it cos(2x) or cos2x?
To prevent such confusion, use parentheses -- i.e., write cos(2x) instead of cos2x. Also, we get a lot of students who are new to writing math expressions as text. I've seen many who write cos2x when they really mean cos2(x). For exponents, the ^ symbol is often used.
 
  • #13
Mark44 said:
To prevent such confusion, use parentheses -- i.e., write cos(2x) instead of cos2x. Also, we get a lot of students who are new to writing math expressions as text. I've seen many who write cos2x when they really mean cos2(x). For exponents, the ^ symbol is often used.
Ok I'll be more careful
 

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