How Do You Solve x+x^2+x^3+x^4... = 14 for x?

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SUMMARY

The equation x + x² + x³ + x⁴ + ... = 14 can be solved using the formula for an infinite geometric series, which is Σa_n x^n = a_0 / (1 - x), applicable for -1 < x < 1. By substituting the series into this formula, one can derive an equation that allows for the determination of x. This method is confirmed as the correct approach to solving the problem, as discussed in previous threads.

PREREQUISITES
  • Understanding of infinite geometric series
  • Familiarity with the formula Σa_n x^n = a_0 / (1 - x)
  • Basic algebraic manipulation skills
  • Knowledge of convergence criteria for series
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  • Study the convergence criteria for infinite series
  • Learn more about geometric series and their applications
  • Explore algebraic techniques for solving equations
  • Review previous discussions on similar mathematical problems
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Mathematicians, students studying calculus, and anyone interested in solving infinite series equations will benefit from this discussion.

Niaboc67
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x+x^2+x^3+x^4... = 14

Find x

Could someone please provide an explanation on how to solve this?
 
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The formula for infinite geometric series is ##\displaystyle \sum_{n=0}^\infty a_n x^n =\frac{a_0}{1-x} ##. But this is true only for ## -1 < x < 1##. Just use this on the series to get an equation in a familiar form.
 
Same question asked in another thread with the same name, so locking this thread.

@Niaboc67, please don't start multiple threads on the same topic.
 

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