How Do You Solve y(x+2) = 9 to Minimize x+y?

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Homework Help Overview

The discussion revolves around the problem of minimizing the sum of two variables, x and y, under the constraint given by the equation y(x+2) = 9. The subject area includes calculus, specifically the application of derivatives and the chain rule.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss taking the derivative of the equation y(x+2) = 9 and express confusion regarding the notation and the introduction of a function f. There are attempts to clarify the correct application of the chain rule and the signs in the derivative.

Discussion Status

The discussion is active, with participants providing corrections and guidance on the derivative calculations. There is recognition of confusion regarding the function to minimize and the correct interpretation of the problem. Multiple interpretations of the derivative and the problem setup are being explored.

Contextual Notes

Participants note the need to clarify the definitions of the variables and the function to minimize, as well as the implications of the signs in their calculations. There is acknowledgment of potential misunderstandings regarding the application of calculus concepts.

Femme_physics
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Homework Statement



Supposed to take the derivative of:

y(x+2) = 9

I think this is one for the chain rule...


Am getting stuck with a fraction with exponent at the bottom and that's a no no that I can't get out of...

The Attempt at a Solution



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I'm confused, what is 'y'? And why do you change to 'f'?
 
You're kind of right (though I don't know why you introduce a function f). Your derivative on line 4 is off by a minus sign; it should read
[tex]\frac{dy}{dx}=-\frac{9}{(x+2)^2}[/tex]

This is the solution: I don't know what you're doing in the next line.
 
Pengwuino said:
I'm confused, what is 'y'? And why do you change to 'f'?

I figured that y and f(x) are the same things just different notation.

The original question is "from all positives numbers X and Y that fulfill y(x+2) = 9, find the two numbers that for them the sum x+y is minimal."

So I thought to take the derivative of y, i.e. f(x) and set it equal to zero. Currently am stuck in the first phase though.

Edit: Oh wait, I did take the derivative successfully, just was off by a minus sign, right? :) Wheepee!
 
cristo said:
You're kind of right (though I don't know why you introduce a function f). Your derivative on line 4 is off by a minus sign; it should read
[tex]\frac{dy}{dx}=-\frac{9}{(x+2)^2}[/tex]

This is the solution: I don't know what you're doing in the next line.

I thought the -9 times the -1 on line 4 give a plus?
 
Femme_physics said:
So I thought to take the derivative of y, i.e. f(x) and set it equal to zero. Currently am stuck in the first phase though.
Don't forget - what is the function that you need to minimize?
 
Femme_physics said:
I thought the -9 times the -1 on line 4 give a plus?
As already noted, you have an extra minus sign. In your work you have
f'(x) = -9(x + 2)-2(-1)
That final (-1) should not be there. Your factor of -9 already includes (-1) from the exponent on x + 2.
 
I think I completely fudged the concept of the question.

diazona said:
Don't forget - what is the function that you need to minimize?

The original question is "from all positives numbers X and Y that fulfill y(x+2) = 9, find the two numbers that for them the sum x+y is minimal."

That final (-1) should not be there.

Ah...thanks.. I thought that's how you use the chainrule, but you're just suppose to take the derivative of the whole thing I see. My bad.So now that I have the right derivative, but apparently my direction of how to solve the question is off because no real values = 0. I'll try to figure it out, I appreciate all the corrections with my basic calculus.
 

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