How Do You Transform Double Summation Limits for a Function of Differences?

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SUMMARY

The discussion focuses on proving the formula for transforming double summation limits of an arbitrary function, specifically the equation t=1Ns=1Nf(t-s)=∑τ=-N+1N-1(N-|τ|)f(τ). Participants confirm its validity through examples with small values of N, such as N=2 and N=3, where both sides yield the same result. A change of variables is suggested, specifically letting τ = t - s, to facilitate the transformation of limits in the summation.

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Homework Statement


I need some advice on prooving this formula (f is an arbitrary function):

\sum^{N}_{t=1}\sum^{N}_{s=1}f(t-s)=\sum^{N-1}_{τ=-Ν+1}(N-|τ|)f(τ)

Thanks in advance
 
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What have you done so far? Have you tried small examples, like N = 2 or N = 3?

RGV
 
Well its easy to see that it works with examples like N=2 or N=3. For example for N=2 the value of both sides is f(1)+f(-1)+2f(0). Same for N=3. I am thinking that maybe I should do a variables change in the first double sums, to end up to a more common summation formula, but I am kinda stuck.

EDIT: We can consider that s and t are integers, or that the arbitrary f() function represents a discrete time signal.
 
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Looks to me like there is a change of index at work there. Since the left side of the equation involves f(t- s) and the other side f(τ), you should immediately think of τ= t- s.
 
could you please help on how the limits of the left side sums would be in that case (τ=t-s)?
 

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