How Does a Ferris Wheel Ride Reveal Physics Principles?

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SUMMARY

The discussion centers on calculating the mass of a woman riding a Ferris wheel with a radius of 16 meters, using scale readings that range from 510 N to 666 N. The relevant physics equations include centripetal acceleration, expressed as a_{c} = mv²/r, and Newton's second law. The participant correctly identifies the forces acting on her at the top and bottom of the ride, leading to the equation 2mg = Nt + Nb. This approach effectively demonstrates the application of physics principles to real-world scenarios.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula
  • Familiarity with Newton's second law of motion
  • Basic knowledge of forces acting on objects in circular motion
  • Ability to interpret and analyze data from graphs
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  • Study the derivation of centripetal acceleration in circular motion
  • Learn how to apply Newton's laws to different physical scenarios
  • Explore the concept of normal force in varying gravitational contexts
  • Investigate the use of digital scales in experimental physics
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Students studying physics, educators teaching mechanics, and anyone interested in the practical applications of physics principles in everyday situations.

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Homework Statement



A woman rides on a Ferris wheel of radius 16m that maintains the same speed throughout its motion. To better understand physics, she takes along a digital bathroom scale (with memory) and sits on it. When she gets off the ride, she uploads the scale readings to a computer and creates a graph of scale reading versus time. Note that the graph has a minimum value of 510 N and a maximum value of 666N. What is the woman's mass?



Homework Equations


a_{c} = \frac{mv^{2}}{r}

and Newtons 2nd law

The Attempt at a Solution



So at the top we have gravity acting on her and the normal force of her seat acting on her which we will call Nt.

so \frac{mv^{2}}{r} = mg - Nt

Then at the bottom, where Nb is the normal force of her seat acting on her

\frac{mv^{2}}{r} = Nb - mg

Then solving these equations I got 2mg = Nt + Nb

I really don't know if I am right about this...can someone please help me?
 
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Hi clarineterr! :smile:
clarineterr said:
So at the top we have gravity acting on her and the normal force of her seat acting on her which we will call Nt.

so \frac{mv^{2}}{r} = mg - Nt

Then at the bottom, where Nb is the normal force of her seat acting on her

\frac{mv^{2}}{r} = Nb - mg

Then solving these equations I got 2mg = Nt + Nb

I really don't know if I am right about this...can someone please help me?

Looks good to me! :biggrin:
 

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