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Riding a Ferri wheel physic problem(help)

  1. Oct 31, 2011 #1
    1. The problem statement, all variables and given/known data

    A student of weight 656 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude of the normal force N on the student from the seat is 581 N. (a) What is the magnitude of N at the lowest point? If the wheel's speed is doubled, what is the magnitude FN at the (b) highest and (c) lowest point?



    2. Relevant equations

    F=(mV^2)r a=v^2/r

    3. The attempt at a solution
    here are my "guesses", becuase i am so confused...
    Fn is same as the centripetal acceleration, which is doward to the center of the wheel.
    m=66.939 Fg = 656N
    -581-656=66.939(-a) what I dont get is that if Fn= a, then this equation is not valid, i mean 581=a? I used this equation becuase it looks like the one in the text book, but I didnt really get the equation.
     
    Last edited: Oct 31, 2011
  2. jcsd
  3. Oct 31, 2011 #2
    this problem is solved, so nvm
     
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