How Does a Hockey Puck Collision Affect Stick Motion?

  • Thread starter Thread starter asaspades
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on the physics of a hockey puck collision with a stick, specifically analyzing the inelastic collision where the puck remains attached to the stick. Key calculations include the final speed of the center of mass (Part A), the distance from the impact point to the center of mass (Part B), and the angular momentum before the collision (Part C). The participants also discuss the moment of inertia and angular velocity of the stick-puck system after the collision (Part D), emphasizing the use of the parallel axis theorem for accurate calculations.

PREREQUISITES
  • Understanding of inelastic collisions in physics
  • Familiarity with center of mass calculations
  • Knowledge of angular momentum and its conservation
  • Application of the parallel axis theorem
NEXT STEPS
  • Study the principles of inelastic collisions in detail
  • Learn about the parallel axis theorem and its applications
  • Explore angular momentum calculations in various systems
  • Investigate the moment of inertia for different shapes and configurations
USEFUL FOR

Physics students, educators, and anyone interested in mechanics, particularly those studying collisions and rotational dynamics in sports contexts.

asaspades
Messages
12
Reaction score
0

Homework Statement


A hockey stick of mass m_{s} and length L is at rest on the ice (which is assumed to be frictionless). A puck with mass m_{p} hits the stick a distance D from the middle of the stick. Before the collision, the puck was moving with speed v_{0} in a direction perpendicular to the stick, as indicated in the figure. The collision is completely inelastic, and the puck remains attached to the stick after the collision.

Part A
Find the speed v_{f} of the center of mass of the stick+puck combination after the collision.
Express v_{f} in terms of the following quantities: v_{0}, m_{p}, m_{s}, \text{and } L.

Part B
After the collision, the stick and puck will rotate about their combined center of mass. How far is this center of mass from the point at which the puck struck? In the figure, this distance is (D−b).

Part C
What is the angular momentum L_{cm} of the system before the collision, with respect to the center of mass of the final system?
Express L_{cm} in terms of the given variables.

Part D
What is the angular velocity \omega of the stick+puck combination after the collision? Assume that the stick is uniform and has a moment of inertia I_{0} about its center.
Your answer for \omega should not contain the variable b.

Homework Equations


MAD_ai_1_a.jpg

MAD_ai_1_b.jpg


Part A velocity of centre of mass u_{cm}=\frac{m_{1}u_{1}+m_{2}u_{2}}{m_{1}+m_{2}}

Part B equation of CoM r_{cm}=\frac{m_{1}r_{1}+m_{2}r_{2}}{m_{1}+m_{2}}

Part C Angular momentum \vec{L}=\vec{r}\times\vec{p}

Part D ?

The Attempt at a Solution


Part A substituting in gives u_{cm}=\frac{0m_{s}+m_{p}v_{0}}{m_{s}+m_{p}}=\frac{m_{p}v_{0}}{m_{s}+m_{p}}=v_{f} because the momentum of the CoM remains unchanged.

Part B We start from the point where the ball strikes the stick, as we already know the distance to the combined CoM from there, D-b, so D-b=\frac{Dm_{s}+0m_{p}}{m_{s}+m_{p}}=\frac{Dm_{s}}{m_{s}+m_{p}}

Part C the perpendicular distance is just D-b so L=(D-b)m_{p}v_{0}=m_{p}v_{0}\frac{Dm_{s}}{m_{s}+m_{p}}

Part D I have no idea where to go here, so any help would be greatly appreciated!
 
Physics news on Phys.org
hi asaspades! welcome to pf! :smile:

(i haven't checked your A to C)

for D, use the parallel axis theorem to find the moment of inertia of the stick about the new centre of mass :wink:
 
  • Like
Likes   Reactions: 1 person

Similar threads

Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
4K
Replies
10
Views
3K
  • · Replies 24 ·
Replies
24
Views
4K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
5
Views
3K