How Does a Pendulum's Period Change on the Moon?

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SUMMARY

The period of a pendulum on the Moon is calculated using the formula T' = √6 * T, where T is the period on Earth and g is the acceleration due to gravity. On the Moon, gravity is one-sixth that of Earth, leading to an increase in the pendulum's period. Additionally, when an elevator moves upward at a constant speed, the period of the pendulum remains unchanged, as the acceleration of the system is zero and no new forces act on the pendulum.

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  • Understanding of pendulum motion and the formula T = 2π√(l/g)
  • Basic knowledge of gravitational acceleration differences between celestial bodies
  • Familiarity with concepts of constant speed and acceleration in physics
  • Ability to manipulate square roots and algebraic expressions
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Homework Statement



on the moon the acceleration of gravity = g/6 if a pendulum has a period T on Earth what will its period be on the moon

Homework Equations



T = 2 pi sqrt(l/g)

The Attempt at a Solution



do you get...
T / sqrt(6
 
Last edited:
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How did you arrive at your answer? Though your answer is wrong, you have all that is needed in the answer(i.e. sqrt(6) and T are needed)
 
ok well i did

T= 2pi sqrt(L/(g/6))
T=2pi sqrtl/g) * sqrt 6
T/sqrt 6 = Period

where Period = 2pi sqrt (l/g)
 
so
T=2\pi \sqrt {\frac{l}{g}}

and the period you want
T'=2\pi \sqrt {\frac{l}{\frac{g}{6}}}

T'=2\pi \sqrt{\frac{l}{g}} *\sqrt{6}

so that

T'=\sqrt{6}T

Where T is the period on Earth
 
oh ok I understand, and i Have another question on pendulums.

A pendulum of length L is suspended from the ceiling of an elevator. When the elevator is at res the period of the pendulum is T. how does the period of the pendulum change when the elevator moves upward with a constant speed?
 
If the elevator moves upward at a constant speed, what is the acceleration of the system? Are there any new forces acting on the pendulum?
 

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