How Does a Pendulum's Period Change on the Moon?

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Homework Help Overview

The discussion revolves around the effect of gravity on the period of a pendulum, specifically comparing conditions on Earth and the Moon. The original poster presents a scenario where the acceleration due to gravity on the Moon is one-sixth that of Earth, leading to questions about how this affects the pendulum's period.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the period of a pendulum and gravitational acceleration, with attempts to derive the period on the Moon based on the formula T = 2π√(l/g). Questions arise about the correctness of the initial attempts and the implications of different gravitational conditions.

Discussion Status

There is an ongoing exploration of the mathematical relationships involved, with some participants providing guidance on the correct application of the formula. Multiple interpretations of the problem are being discussed, particularly regarding the transition from Earth to Moon conditions.

Contextual Notes

Participants are also considering a related question about the behavior of a pendulum in an elevator moving at constant speed, prompting further inquiry into the effects of acceleration and forces on the pendulum's period.

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Homework Statement



on the moon the acceleration of gravity = g/6 if a pendulum has a period T on Earth what will its period be on the moon

Homework Equations



T = 2 pi sqrt(l/g)

The Attempt at a Solution



do you get...
T / sqrt(6
 
Last edited:
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How did you arrive at your answer? Though your answer is wrong, you have all that is needed in the answer(i.e. sqrt(6) and T are needed)
 
ok well i did

T= 2pi sqrt(L/(g/6))
T=2pi sqrtl/g) * sqrt 6
T/sqrt 6 = Period

where Period = 2pi sqrt (l/g)
 
so
[tex]T=2\pi \sqrt {\frac{l}{g}}[/tex]

and the period you want
[tex]T'=2\pi \sqrt {\frac{l}{\frac{g}{6}}}[/tex]

[tex]T'=2\pi \sqrt{\frac{l}{g}} *\sqrt{6}[/tex]

so that

[tex]T'=\sqrt{6}T[/tex]

Where T is the period on Earth
 
oh ok I understand, and i Have another question on pendulums.

A pendulum of length L is suspended from the ceiling of an elevator. When the elevator is at res the period of the pendulum is T. how does the period of the pendulum change when the elevator moves upward with a constant speed?
 
If the elevator moves upward at a constant speed, what is the acceleration of the system? Are there any new forces acting on the pendulum?
 

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