How Does a Window Washer Adjust Force to Ascend at a Constant Speed?

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SUMMARY

The window washer must exert a downward force equal to half the weight of the combined mass of herself and the bucket to ascend at a constant speed using a pulley system. Given a total mass of 75 kg, the weight is calculated as 735 N (using F=ma with g=9.8 m/s²). When using a single rope, the force required is 367.5 N. In a scenario with two massless pulleys, the tension in the ropes must be considered, leading to the conclusion that the total tension exerted by three ropes equals the weight of the washer and bucket, resulting in the equation 3*T=mg.

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Homework Statement


A window washer pulls herself up using a pulley-bucket apparatus. How hard must she pull downward to raise herself slowly at constant speed? The mass of the person plus the bucket is 75 kg.


Homework Equations


F=ma


The Attempt at a Solution


I don't know what I'm doing wrong. Is the force she has to pull downward not equal to the weight? I get (9.8)(75)=735N. It says use two sig figs and I've tried both 7.4x10^2 and 7.3x10^2 N. I hate mastering physics!
 
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If she's using pulleys, then the force is NOT necessarily equal to the weight. That's the whole point to using pulleys. You'd better describe the pulley system.
 
looks like this http://answerboard.cramster.com/physics-topic-5-139868-0.aspx
 
Last edited by a moderator:
Obviously the ropes must exert a total force on "washer + bucket" that equals its weight. Hint: How many times does the rope pull on "washer + bucket"?
 
hmm so the ropes each carry half the weight. So 735N/2?
 
rwx1606 said:
hmm so the ropes each carry half the weight. So 735N/2?
Yep. (Fix that typo.)

She only pulls on one rope, so she just needs to exert a force equal to the needed rope tension. Which is half the weight.
 
What if the problem is changed a bit?

Suppose there are two massless pulleys, and the massless rope is attached to the ceiling.
_______
| /O\ The 75kg window washer stands on the weightless platform and pulls on the
| | | string at point "x." How hard does she have to pull to slowly raise herself at
| | | constant velocity?
| x |
| _ |
\ O/
 
AlexWyler said:
What if the problem is changed a bit?

Suppose there are two massless pulleys, and the massless rope is attached to the ceiling.
_______
| /O\ The 75kg window washer stands on the weightless platform and pulls on the
| | | string at point "x." How hard does she have to pull to slowly raise herself at
| | | constant velocity?
| x |
| _ |
\ O/

If I'm reading your cartoon correctly, then you have three massless ropes connected only by massless pulleys. In that case the tension in all three ropes is the same. So they all exert the same tension T on the platform and washer. So 3*T=mg. Conclusion?
 

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