How Does Adiabatic Compression Affect Entropy and Temperature in Nitrogen Gas?

  • Thread starter Thread starter imy786
  • Start date Start date
  • Tags Tags
    Adiabatic Entropy
Click For Summary

Homework Help Overview

The discussion revolves around the adiabatic compression of nitrogen gas, specifically examining the effects on entropy and temperature. The problem involves a sample of nitrogen gas undergoing a change in volume and the implications of this change under adiabatic conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the change in entropy and question the assumptions regarding heat flow during adiabatic processes. There are attempts to clarify the relationship between pressure, volume, and temperature under adiabatic conditions.

Discussion Status

The discussion includes various interpretations of the change in entropy, with some participants suggesting that heat flow is involved, while others emphasize the definition of adiabatic processes. There is an ongoing exploration of the implications of the adiabatic accessibility index on entropy changes.

Contextual Notes

Some participants note the assumption of reversible adiabatic compression and question the implications of temperature changes on entropy. There is also mention of the ideal gas behavior of nitrogen under the given conditions.

imy786
Messages
321
Reaction score
0

Homework Statement



A sample of 5 moles of nitrogen gas (γ = 1.40) occupies a volume of 3.00 × 10^−2 m3 at a pressure of 2.00 × 10^5 Pa and temperature of 280 K.
The sample is adiabatically compressed to half its original volume. Nitrogen behaves as an ideal gas under these conditions.

a)What is the change in entropy of the gas?

b)Show from the adiabatic condition and the equation of state that TV γ −1 remains constant, and hence determine the final temperature of the gas.

Homework Equations





The Attempt at a Solution



(a)

W=PV
Change in V= (3-1.5) *10^2= 1.5^10*-2

W= 2.00 × 10^5 * 1.5^10*-2
= 3*10^3 J

U=Q+W
Q= -W
Q= - 3*10^3


S= Q/T
= - 3*10^3/ 280= 10.7 JK^-1

-------------------------------------------

(b)

adiabatic condition PV^γ= A

equation of state : PV= nRT

(nRT)^gamma=A

A* V γ−1 = P

P= nRT/v

nRT/v= A* V γ−1

nRT/vA = V γ−1

TV γ −1 remains constant..
 
Physics news on Phys.org
imy786 said:

Homework Statement



A sample of 5 moles of nitrogen gas (γ = 1.40) occupies a volume of 3.00 × 10^−2 m3 at a pressure of 2.00 × 10^5 Pa and temperature of 280 K.
The sample is adiabatically compressed to half its original volume. Nitrogen behaves as an ideal gas under these conditions.

a)What is the change in entropy of the gas?

b)Show from the adiabatic condition and the equation of state that TV γ −1 remains constant, and hence determine the final temperature of the gas.

Homework Equations





The Attempt at a Solution



(a)
...
S= Q/T
= - 3*10^3/ 280= 10.7 JK^-1
Assume it is compressed reversibly and adiabatically (the external pressure is slightly higher than internal pressure during compression). Is there any flow of heat into/out of the gas or into or out of the surroundings? So what is the change in entropy?

(b)

adiabatic condition [itex]PV^\gamma = A[/itex]

equation of state : PV= nRT
...
I find it a little difficult to follow your reasoning. Substitute P = nRT/V into [itex]PV^\gamma = A[/itex] to get

[tex]nRTV^{\gamma-1} = A[/tex]

AM
 
(a) there is flow of heat to the system of temp 300K.
The change in entropy has doubled as the volume has halved.
 
What is the adiabatic accessibility index doing? rising falling remaining constant? this will tell you what the change in entropy is.
 
adiabatic accessibility index remains constant.
Therefore change in entropy is constant no change.
 
imy786 said:
(a) there is flow of heat to the system of temp 300K.
The change in entropy has doubled as the volume has halved.
Careful. Adiabatic means no heat flow. Temperature changes due to internal energy increasing as a result of work being done on gas. But this does not mean there is heat flow.

AM
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
3
Views
2K