How Does an Electron Behave Near a Nucleus?

  • Thread starter Thread starter ncm2
  • Start date Start date
  • Tags Tags
    Electron Nucleus
Click For Summary
SUMMARY

The discussion focuses on calculating the behavior of an electron near a neptunium nucleus, specifically at a distance of 3.10 × 10-10 m. The electric field magnitude is confirmed as 1.39 × 1012 N/C, and the force on the electron is calculated to be 2.23 × 10-7 N using F=qE. For the period of the electron's motion, the correct approach involves using the formula F = mv2/r instead of F=ma. The final speed of the electron is determined to be 8.72 × 106 m/s.

PREREQUISITES
  • Understanding of electric fields and forces (F=qE)
  • Familiarity with classical mechanics concepts (F=mv2/r)
  • Knowledge of circular motion and period calculations
  • Basic proficiency in algebra and unit conversions
NEXT STEPS
  • Study classical mechanics, focusing on circular motion and centripetal force
  • Learn about electric fields and forces in atomic physics
  • Explore the relationship between speed, distance, and time in circular orbits
  • Investigate the properties of neptunium and its atomic structure
USEFUL FOR

Students in physics, particularly those studying atomic structure and electron behavior, as well as educators seeking to clarify concepts related to electric fields and classical mechanics.

ncm2
Messages
14
Reaction score
0
I am sure it is easy to do, but I just can't seem to figure the question out. It is 4 parts and I got the first 2 parts. If someone can give me the steps with the numbers (already handed in assignment, and got it incorrect), that would be much appreciated.


1. What is the magnitude of the electric field at a distance of 3.10 ×10-10 m from a neptunium nucleus?
The answer I got is 1.39×1012 N/C.

2. What is the magnitude of the force on an electron at that distance?
2.23×10-7 N F=qE.

3. Treating the electron classically, that is, as a point object that can move around the nucleus at reasonably slow speeds, what is the period of the electron's motion?
The answer is 2.23×10-16 s but I am unable to calculate this.

I tried taking the Force from part 2 and using F=ma. Then using a to find velocity. Then used that to find T.

4. Again treating the electron classically, how fast it it moving?
The answer is 8.72×106 m/s, again no idea what I did wrong but I can't find this answer.



Many thanks.
 
Physics news on Phys.org
I wouldn't start with F=ma for question 3. I think F = mv2/r would do the trick.

Once you have v you can work out what the distance is for the electron to make one complete orbit (hint, you already have the radius).

And then of course, speed = distance/time.

This gives the answers to both (3) and (4)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
5
Views
2K
Replies
7
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K