How Does Angular Velocity Change After Inelastic Collision?

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Homework Help Overview

The problem involves an inelastic collision between two masses, where one mass collides with another mass initially at rest and they stick together. The focus is on expressing the angular velocity in terms of the initial speed of the moving mass.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of conservation laws, specifically questioning the use of linear momentum due to constraints on the rotating mass. There is also exploration of angular momentum as a conserved quantity.

Discussion Status

Participants are actively engaging with the problem, raising questions about the setup and assumptions, particularly regarding the role of the axis of rotation and the diagram's clarity. Some guidance has been offered regarding the conservation of angular momentum.

Contextual Notes

There is ambiguity regarding the diagram and the role of the mass m2, particularly whether it is fixed or free to rotate, which affects the application of physical principles.

Jalo
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Homework Statement



A mass m1 with speed v1i colides with a mass m2 of length 1m, initially at rest, and gets stuck with it.
(a) Express the angular velocity in functon of v1i. (m=m1=m2)


122m0z6.jpg


Homework Equations



w=v/r

The Attempt at a Solution



Since the collision is totally inelastic I can say
m1*vi1=(m1+m2)vf
Since all masses are equal I can say
vi1=2vf⇔vf=v1i/2
Since w=v/r
w=vf/r⇔w=0.5*v1i/0.5⇔w=v1i

This is wrong for some reason... Can anyone lead me in the correct way?

Thanks.
D.
 
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If the length of the bar is 1, then the radius of a circle that the bar makes as it rotates 360 degrees means r=1. Thus w= 0.5V1i/1 = V1i/2.
 
I don't quite understand the diagram. What's that ball like thing on top of m2? Is m2 fixed at some point?
 
Doc Al said:
I don't quite understand the diagram. What's that ball like thing on top of m2? Is m2 fixed at some point?

Doc Al has a great point. More explanation is needed. I just assumed the ball at the top of the bar was an axis of rotation, but I could be wrong.
 
It doesn't say nothing about the ball, so I'm pretty sure it's the axis of rotation
 
Jalo said:
It doesn't say nothing about the ball, so I'm pretty sure it's the axis of rotation
Assuming that m2 is constrained to rotate about that axis, you cannot apply conservation of linear momentum. (The axis will exert forces on m2.)

But what other quantity is conserved?
 
Angular momentum?
 
Jalo said:
Angular momentum?
Right!
 

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