How Does Bullet Speed Affect Pendulum Motion?

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SUMMARY

The discussion focuses on the physics of bullet speed affecting pendulum motion, specifically analyzing a bullet of mass 0.0175 kg passing through a pendulum bob of mass 1.3 kg. In Part A, the critical speed for the pendulum bob to complete a vertical circle is calculated to be 975.61 m/s using conservation of momentum and energy principles. Part B addresses the scenario where the pendulum bob is suspended from a flexible cord, requiring consideration of centripetal force and gravitational force at the top of the swing. The participant successfully deduces that the tension in the cord is negligible at the top of the pendulum's arc.

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  • Understanding of conservation of momentum and energy principles
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Homework Statement



diagram: http://goo.gl/uPl0

Part A
A bullet of mass 0.0175 kg and speed vb passes completely through a pendulum bob of mass 1.3 kg. The bullet emerges with a speed 0.5vb. The pendulum bob is suspended by a stiff rod of length 1.1 m and negligible mass. The acceleration of gravity is 9.8 m/s2. What is the critical value v, such that when vb > v , the pendulum bob will barely swing through a complete vertical circle?

Part B

Suppose that the pendulum bob is suspended from a light flexible cord instead of a stiff rod.
Now what is the minimum value of v such that the pendulum bob will swing through a
complete vertical circle?

2. The attempt at a solution

I was able to get part A by using conservation of momentum and conservation of energy and ended up with 975.61 m/s for v.

However, I am stuck on part B and do not know how to proceed. I know it has something to do with the tension of the cord, but am not exactly how to factor that in.

Any help would be much appreciated. Thanks!
 
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help anyone?
 
never mind, i got it! i figured out that at the top of the pendulum, centripetal force had to be equal to the force of gravity because there is no tension to support the bob.
 

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