How Does Charge Flow in Series Capacitors Affect Electric Field Balance?

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SUMMARY

The discussion centers on the behavior of charge flow in series capacitors and the resulting electric field balance. When two capacitors are connected in series, the outer plates induce opposite charges on the inner plates, creating a dipole effect. The equilibrium condition is achieved when the electric fields from the charges on the plates cancel each other out, resulting in no net movement of electrons in the connecting wire. This phenomenon explains why charges do not flow between the inner plates despite the attractive forces present.

PREREQUISITES
  • Understanding of capacitor theory and charge distribution
  • Knowledge of electric fields and their behavior in conductive materials
  • Familiarity with series circuits and their characteristics
  • Basic principles of electrostatics and induction
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  • Study the principles of electrostatic induction in capacitors
  • Learn about the effects of electric fields in conductive materials
  • Explore charge distribution in series and parallel capacitor configurations
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pardesi
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consider the plates ofa capacitor suppose u just have two capacitors connected in series then consider the two plates not connected to the battery that form a seprate system .one of them has +Q and the other -Q
then how is that there is no flow of charges between them because one of them repells electron(considering the net effect of that and it's 'conjugate' plate) and other attracts (considering the net effect of this it's 'conjugate' plate)
 
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In a real capacitor there is a flow because the insulating material between the plates is obviously never a perfect insulator.

It's a common fault in electronics designs to produce a circuit which doesn;t work where the capcitors never fully charge because of the leakage current.
 
but the wires between the plates of two capacitors is atleast theoritically perfectly conducting
 
does someone have any idea...
 
pardesi said:
consider the plates ofa capacitor suppose u just have two capacitors connected in series then consider the two plates not connected to the battery that form a seprate system .one of them has +Q and the other -Q

then how is that there is no flow of charges between them ?



For the same reason a neutral piece of paper is attracted to a positivily charged comb.

It happens because, even though the piece of paper is originally neutral, the positive charge on the comb induces a dipole field on the paper.

Likewise in your case, each outer plate (connected to the battery) "induces" opposite charge on the inner plates. In effect the formerly neutral inner plates (connected together) 'act as if' they are a large "induced" dipole.

The +Q and -Q on the inner plates are only there because of induction. They don't neutralize each other for the same reason an 'induced' dipole doesn't neutralize itself.
The charges in an E field arrange themselves in such a way to try to neutralize the externally applied FIELD.

Creator:biggrin:
 
Last edited:
but my question is about the field between +Q of one plate and -Q of other plate
 
pardesi said:
but my question is about the field between +Q of one plate and -Q of other plate

If I understand correctly, this is what you have in mind:

... +Q1 -Q2 +Q3 -Q4
------| |------| |-------

Absolute values of all charges are equal (Q1=Q2=Q3=Q4), if both capacitors are equal. They have different labels to help the discussion. You are asking, why charges -Q2 and +Q3 do not move toward each other. Right? Indeed, there is attraction between them, and the wire presents a convenient path.

The answer is that -Q2 is also attracted to +Q1, and +Q3 is also attracted to -Q4. So, in the equilibrium situation it is unlikely that Q2=Q3=0. The equilibrium values of charges Q1=Q2=Q3=Q4 can be found by knowing capacitance values and the applied voltage.

Eugene.
 
no not that the capacitors move towards each other...i was talking about the intermediate electrons in the wire ...just near te negative charge they are pushed and juts near the positive they are attracted so how come the charging in this segment ever stop
 
pardesi said:
no not that the capacitors move towards each other...

I haven't implied that capacitor plates are moving. I was talking about moving charges.


pardesi said:
i was talking about the intermediate electrons in the wire ...just near te negative charge they are pushed and juts near the positive they are attracted so how come the charging in this segment ever stop

There is no electric field in the wire connecting plates -Q2 and +Q3. The field created by charges -Q2 and +Q3 is exactly compensated by the field created by charges +Q1 and -Q4. Therefore, electrons in this wire are not moving.

I am not sure if you agree with my explanation, perhaps, I didn't understand your question. What is the charge distribution among all four plates, in your opinion?

Eugene.
 
  • #10
actually it is this fact that is worrying if the charges are so distributed that the field cancel out then the charging never stops end evn if they didn't it wouldn't (may be...)
i don't have any idea sbout charge distribution
 
  • #11
pardesi said:
actually it is this fact that is worrying if the charges are so distributed that the field cancel out then the charging never stops end evn if they didn't it wouldn't (may be...)

I am not sure we are talking about the same thing. The equilibrium condition is exactly when forces acting on each charge in the system are balanced. In this situation, the electric field in the wire is zero, so electrons are not moving along the wire, and the charges on capacitors plates are not changing.

Eugene.
 

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