- #1

Adesh

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We have three capacitors, with capacitances ##C_1##, ##C_2## and ##C_3##. Plates are labelled as ##A_1, A_2, A_3 ... A_6##. Point P is connected to the positive terminal of the battery and point N is connected to the negative terminal of the battery, positive terminal of the batter will provide a charge of ##+Q## to the plate ##A_1## and a charge of ##-Q## to the plate ##A_6##. Due to mutual induction we will get a charge distribution as shown in the diagram. (Sorry if my diagram contains too much letters in a small space). Now, my book says that

let the point N be at potential 0, as point N is connected to the plate ##A_6## therefore plate ##A_6## will also be at potential 0. Assume point P to be at potential ##V##, so the plate ##A_1## will also be at potential ##V##. Let plate ##A_2## be at potential ##V_1##,

*since it is connected to plate ##A_3## we will have the potential of plate ##A_3## also as ##V_1##*. Similarly, assume plate ##A_4## to be at potential ##V_2## so will be the plate ##A_5## as they are connected.

Now, the problem is since the plate ##A_2## and ##A_3## are oppositely charged how can they be at same potential? My intuition tells me that there will be a net field going from ##A_3## to ##A_2##, but I also know that they are connected by a conducting wire and no field exist inside the conductor. I'm just unable to connect the dots, can someone please clear this doubt.

Thank you.