How Does Connecting a Wire Affect Light Bulbs in an Inductive Circuit?

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Homework Help Overview

The discussion revolves around a problem involving an inductive circuit with a solenoid and two light bulbs connected in series. The scenario includes the introduction of an additional wire loop around the solenoid and questions about the effects on the light bulbs when this wire is connected.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the implications of connecting a wire in an inductive circuit, questioning how it affects the current and brightness of the light bulbs. There are considerations about symmetry in the circuit and the role of resistance in the flow of current.

Discussion Status

Several participants express uncertainty about the outcomes, with some suggesting that the light bulbs may continue to glow with the same intensity, while others propose that the added wire could provide a path of lesser resistance. The discussion is ongoing, with no definitive conclusions reached yet.

Contextual Notes

Participants note the complexity of the situation and the potential for experimental verification, indicating a desire to understand the underlying principles of electromagnetic induction and circuit behavior.

fhqwgads2005
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I was recently given a problem I can't quite wrap my head around. Here's the situation:

shttp://pics.bbzzdd.com/users/theman/inductorbulbs.gif

(you'll have to copy the link, - the s, into your address bar)

Oh-- and i just realized a mistake with the drawing, the dots should be x's to indicate the field is going into the page.

We have a solenoid creating an increasing magnetic field into the screen. A wire loop goes around the solenoid with two lightbulbs connected in series. The induced EMF is counter clockwise. Then, another wire is connected as shown to the top and bottom of the wire loop.

Question: what happens to the lightbulbs when the wire is connected?

My initial thought was that the light bulb on the left would turn off (short circuited) and the one on the right would get brighter.

But then I was thinking, what if the wire were just flipped over and was on the other side. Would the light bulbs then switch, and the right one would go off? I don't see why this would be true. Why should the physical orientation of the added wire affect the circuit?
 
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You are right in arguing that this is a symmetric situation.

I'm not entirely sure but I think nothing will happen i.e. the bulbs will continue to glow with the same intensity. Like I said, I'm not sure so I'm waiting for a concrete answer too.
 
At a first guess, I'd say that nothing will happen.

Consider the closed loop consisting of the wire between the two bulbs. The rate of change of magnetic flux within that loop stays the same. Now consider the loop of wire which you have attached, and the closed loop formed by that on the left hand side of the figure. The flux passing through that is zero, and the rate of change of flux passing through it is also zero, so the attachment of the wire should do nothing.

(Note: This is simply what I remember off the top of my head. It has been more than four years since I studied this in high school, and I (regrettably) haven't touched physics since.)
 
The problem is though, that the attached wire offers a path of lesser resistance through which the current can flow, instead of through one of the bulbs. I think I might actually try and build this soon and see what it actually does. This is a very strange situation indeed.
 

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