How does constant percent rate of change apply to exponential expressions?

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Homework Help Overview

The discussion revolves around a problem related to exponential decay in the context of cooling temperatures. The original poster is trying to understand how a constant percent rate of change applies to the cooling of a pot of stew, specifically regarding the time it takes for the temperature difference to decrease by 50%.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of temperature differences and how they relate to the concept of halving in exponential decay. Questions arise about the interpretation of a 50% change in temperature difference versus absolute temperature changes.

Discussion Status

Some participants have clarified the misunderstanding regarding the temperature changes, emphasizing that the relevant factor is the difference from the target temperature of 20 degrees Celsius. There is acknowledgment of the confusion surrounding the concept of halving the temperature difference.

Contextual Notes

Participants are grappling with the definitions and assumptions related to temperature differences and the specific context of the problem, particularly the target temperature and how it affects the calculations.

kevinshen18
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So this question is from Khan Academy. I understood the first part and chose the correct function, but the second question(from 40 degrees to 30 degrees change) explanation confused me.
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QUESTION:
Ajay made a steaming pot of stew. When he turned the stove off, the stew’s temperature was 70° Celsius, and it started cooling down to the room temperature, which was 20° Celsius.
The following expressions give the temperature of the stew, m minutes after Ajay turned the stove off. They are all equivalent, save for some rounding of the coefficients.
Which expression best highlights the amount of time it takes the difference between the stew’s temperature and the room’s temperature to drop by 50%?

20+50·0.50^12m

20+0.5·100^0.92m

20+50·0.20^052m

How long will it take the stew's temperature to go from 40° to 30°? Round your answer, if necessary, to two decimal places.
 
SOLUTION/EXPLANATION:
All the expressions are either given in the form 20+A·B^am where a is a constant number, or they can be quickly transformed to this form. In this form, A·B^am is the difference between the stew's temperature and the room's temperature. This implies that the difference between the temperatures is multiplied by B when a·m=1.
For instance, let's consider the expression 20+50·0.20^052m. The expression 0.052m is equal to 1 when m is approx = 19.23 minutes. This tells us that the difference between the temperatures is multiplied by 0.2 every 19.23 minutes. This is interesting information, but what we really want to know is how often the difference drops by 50%, not how often it drops by 80%.
The difference between the temperatures dropping by 50% is the same as the difference multiplied by 0.5. So if the expression contains 0.5 at the base of the exponentiation, we know this expression highlights the amount of time it takes the difference between the temperatures to drop by 50%.
The expression that has 0.5 at the base is 20+50·0.50^12m, so this is the expression we are looking for.
20+50·0.50^12m implies that the difference between the temperatures is multiplied by 0.5 when 0.12m=1. In other words, the difference drops by 50% when m is approx = 8.33 minutes.
Since the room's temperature is 20°, the corresponding temperature differences for the stew's temperature being 40° and 30° are differences of 20° and 10°.
We know that the percent rate of change of exponential expressions is constant. This means that the time it takes the difference between the temperatures to drop by 50% is the same whether the absolute change is from 50° to 25° or from 20° to 10°. Therefore, the amount of time it will take the stew's temperature to go from 40° to 30° is 8.33 minutes.
The expression that best highlights the amount of time it takes the difference between the stew’s temperature and the room’s temperature to drop by 50% is:
20+50·0.50^12m
The amount of time it will take the stew's temperature to go from 40° to 30° is 8.33 minutes.
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I got confused when they said the temperature would take the same amount of time to go from 20 to 10 and 40 to 30. But 40 to 30 isn't a -50% change. How does that work?
 

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I got confused when they said the temperature would take the same amount of time to go from 20 to 10 and 40 to 30. But 40 to 30 isn't a -50% change. How does that work?
... that is because you have misread what they said.
You have to realize that the target temperature is 20deg. It is the difference, between the actual temperature and the target, that has to halve.

So the stew going from 40deg to 30deg means that the temperature difference goes from (40-20)deg to (30-20)deg. which is 20-10deg ... which is a halving of the difference.
 
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Simon Bridge said:
... that is because you have misread what they said.
You have to realize that the target temperature is 20deg. It is the difference, between the actual temperature and the target, that has to halve.

So the stew going from 40deg to 30deg means that the temperature difference goes from (40-20)deg to (30-20)deg. which is 20-10deg ... which is a halving of the difference.

Ah Okay, I see! Thank you!
 
No worries: it gets confusing when they talk like that :)
 

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