How Does Doting a Unit Vector With a Vector A Affect the Result?

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Doting a vector A with a unit vector yields the scalar projection of A in the direction of the unit vector, which is often interpreted as the magnitude of A in that direction. The correct answer to the homework question is option e, although the wording is criticized for being unclear. The discussion highlights that the result can be negative if the angle between the vectors exceeds 90 degrees. There is a distinction made between interpretations in British and American English regarding the phrasing of the options. Overall, the conversation emphasizes the importance of clarity in mathematical questions.
Tiven white
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Homework Statement


When a vector A is dotted with a unit vector, the result is...
Select one:
a. zero
b. the magnitude of the unit vector in the direction of A.
c. the magnitude of A.
d. the angle between A and the unit vector.
e. the magnitude of A in the direction of the unit vector.


Homework Equations





The Attempt at a Solution


i said the answer is e reason being the unit vector is a form of direction and when multiplied by a vector it will give the magnitude of A in the corresponding direction.
is this correct?
 
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Yes, that's the answer they're looking for, but the question is not worded very well. Magnitude implies that the result is positive, and ##\vec{A}\cdot \hat{u}## could very well be negative if the angle between the two vectors is greater than 90 degrees. ##\vec{A}\cdot\hat{u}## is the scalar projection of ##\vec{A}## in the direction of ##\hat{u}##.
 
Tiven white said:

Homework Statement


When a vector A is dotted with a unit vector, the result is...
Select one:
a. zero
b. the magnitude of the unit vector in the direction of A.
c. the magnitude of A.
d. the angle between A and the unit vector.
e. the magnitude of A in the direction of the unit vector.


Homework Equations





The Attempt at a Solution


i said the answer is e reason being the unit vector is a form of direction and when multiplied by a vector it will give the magnitude of A in the corresponding direction.
is this correct?
Yes. I would call it the "component" of A in the direction of the unit vector.
 
I agree, the wording is poor. In British English, I would interpret b and e as

b. (the magnitude of the unit vector), (in the direction of A.)
e. (the magnitude of A), (in the direction of the unit vector.)

which makes correct answer "none of the above".

If you interpret it as
b. (the magnitude) of (the unit vector in the direction of A.)
e. (the magnitude) of (A in the direction of the unit vector.)

which makes sense in British English for b, but not for e, the answer would be e.
 
I don't have any problem interpreting the above question. I think the answer #4 above unnecessarily complicates things by inserting groupings that make no sense. Vela makes a good point about the sign however.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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