How does electricity flow through the body?

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Electricity in the body primarily flows through ions, with positive ions moving toward negatively charged areas and vice versa. This movement does not neutralize the current because redox reactions at both ends of the circuit maintain charge balance, allowing continuous flow. While electricity is often described as the movement of electrons, it can also be understood as the transfer of charge, which includes the movement of ions. Pure water is not conductive, but dissolved salts enhance conductivity by providing mobile ions. Understanding these principles is crucial for grasping how electrical signals, such as action potentials, function in biological systems.
  • #31
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  • #32
My point is simply that without the plasma membrane, integral membrane proteins such as ion channels and pumps, and ATP, living cells could not establish a resting membrane potential.
http://en.wikipedia.org/wiki/Action_potential
Ions cross the cell membrane under two influences: diffusion and electric fields. A simple example wherein two solutions - A and B - are separated by a porous barrier illustrates that diffusion will ensure that they will eventually mix into equal solutions. This mixing occurs because of the difference in their concentrations. The region with high concentration will diffuse out toward the region with low concentration. To extend the example, let solution A have 30 sodium ions and 30 chloride ions. Also, let solution B have only 20 sodium ions and 20 chloride ions. Assuming the barrier allows both types of ions to travel through it, then a steady state will be reached whereby both solutions have 25 sodium ions and 25 chloride ions. If, however, the porous barrier is selective to which ions are let through, then diffusion alone will not determine the resulting solution. Returning to the previous example, let's now construct a barrier that is permeable only to sodium ions. Since solution B has a lower concentration of both sodium and chloride, the barrier will attract both ions from solution A. However, only sodium will travel through the barrier. This will result in an accumulation of sodium in solution B. Since sodium has a positive charge, this accumulation will make solution B more positive relative to solution A. Positive sodium ions will be less likely to travel to the now-more-positive B solution. This constitutes the second factor controlling ion flow, namely electric fields. The point at which this electric field completely counteracts the force due to diffusion is called the equilibrium potential. At this point, the net flow of this specific ion (in this case sodium) is zero.
 
  • #33
You are right in saying that when there is a concentration gradient between two solutes separated by a semi-permeable membrane, ions that are permeable to the membrane will move down their concentration gradient until the flow due to the electrical gradient equally opposes the flow due to the concentration gradient. In order for this to occur however, there must be an existing concentration gradient between the two solutes. In http://www.ncbi.nlm.nih.gov/bookshelf/br.fcgi?book=neurosci&part=A132&rendertype=figure&id=A134" the concentration gradient is formed by pouring solutes of different concentrations into each chamber, and in the quoted paragraph the concentration gradient is formed by letting solution A have 30 Na+ and Cl- ions and letting solution B have 20 Na+ and Cl- ions, but in a living cell the concentration gradient is formed by ion pumps such as Na/K-ATPase moving ions against their concentration gradient.
 
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  • #34
In fact, it doesn't matter (for me) if pumps exist or not. The only interresting thing is ions that are close to the membrane. If they are effectively at this place then pumps can't function and action potential can't occur.
 
  • #35
Pumps do function. They're using energy, be it ATP (K/Na pumps) or some other reaction (COX).

You don't necessarily have a case where there's an equilibrium between electrical and concentration gradients, or any equilibrium at all. The inner mitrochondrial membrane, for instance, is not at equilibrium electrically or concentration-wise. (Although more so with respect to concentration because a certain amount of ion exchange occurs.)
 
  • #36
alxm said:
Pumps do function. They're using energy, be it ATP (K/Na pumps) or some other reaction (COX).

You don't necessarily have a case where there's an equilibrium between electrical and concentration gradients, or any equilibrium at all. The inner mitrochondrial membrane, for instance, is not at equilibrium electrically or concentration-wise. (Although more so with respect to concentration because a certain amount of ion exchange occurs.)

1/ This kind of assertion doesn't bring any argument against my allegation. I'll bring a little drawing.
2/ I know there are many organelles that are not electrically neutral but if they aren't neutral why don't you take them into account?
 
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  • #37
Deoxyribose said:
but in a living cell the concentration gradient is formed by ion pumps such as Na/K-ATPase moving ions against their concentration gradient.

http://www.ncbi.nlm.nih.gov/pubmed/9325376
Contribution of the Na+ pump to resting axonal potential is estimated at -7 mV. Ouabain (10 microM to 10 mM) evoked a dose-dependent depolarization that was maximal at >/=1 mM, depolarizing the nerves to approximately 35-40% of control after 60 min.
Not 10 seconds as stated and the contribution of Na K pump is often < to 10 % of the resting potential.
 
  • #38
somasimple said:
http://www.ncbi.nlm.nih.gov/pubmed/9325376

Not 10 seconds as stated and the contribution of Na K pump is often < to 10 % of the resting potential.

Did you misread my statement?
Deoxyribose said:
but in a living cell the concentration gradient is formed by ion pumps such as Na/K-ATPase moving ions against their concentration gradient.
Notice that I said the concentration gradient is formed by ion pumps such as Na/K-ATPase, not that the concentration gradient is formed by Na/K-ATPase.
Inhibiting energy metabolism (CN- and iodoacetate) during high-dose ouabain (1-10 mM) exposure caused an additional depolarization, suggesting additional ATP-dependent, ouabain-insensitive ion transport systems.
This does show that Na/K-ATPase is not the only ion pump involved in maintaining the resting membrane potential. It also shows that ATP is necessary to power those ion pumps.
In addition, maintenance of membrane potential is critically dependent on continuous Na+ pump activity due to the relatively high exchange of Na+ (via the above mentioned routes) and K+ across the membrane of resting optic axons.

So the membrane potential is critically dependent on Na+ pumps. Na+ pumps are ion pumps. This evidence further supports my claim that concentration gradients in a living cell are formed by ion pumps and that ion pumps are necessary to maintain resting membrane potential.

To sustain electrogenesis, transmembrane K+ and Na+ gradients maintain axons in a polarized state and provide energy for signaling, respectively. These electrochemical gradients are established by energy-dependent ion transport systems, the most important of which is the Na+,K+-ATPase

These were the second and third sentences of the introduction.
 
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  • #39
http://www.ncbi.nlm.nih.gov/pubmed/2446906
The inward movement of sodium ions and the outward movement of potassium ions are passive and the reverse movements against the electrochemical gradients require the activity of a metabolism-driven Na+/K+-pump.
http://www.ncbi.nlm.nih.gov/pubmed/6320455
Pumped and transported components of ionic flux have been added to passive electrodiffusive components.
A plot of the membrane potential versus log [K]o with an electrogenic Na pump present gives a curve with slopes both greater than and less than 58 mV per 10-fold concentration change. Over a middle range of [K]o values, the slope is 58 mV. The slope of Em versus log [K]o curves is, therefore, not a very sensitive test for the presence of an electrogenic pump.

If pumps acts only for less than 10% what is the resting 90% made of? Perhaps, passive?
 
  • #40
The inward movement of sodium ions and the outward movement of potassium ions are passive
Let's describe all the events that happen simultaneously:
1/ Sodium movement balanced with chloride
sodium is inward and Na ions stick to the internal membrane
chloride ions stay out, and balance the Na charge, across the external membrane
2/ Potassium movement balanced with chloride
potassium is outward and K ions stick to the external membrane
chloride ions stay in, and balance the K charge, across the internal membrane

Now let's see what happens on each side:
1/ Internal side:
sodium is inward and Na ions stick to the internal membrane
chloride ions stay in, and balance the K charge, across the internal membrane
2/ External side
chloride ions stay out, and balance the Na charge, across the external membrane
potassium is outward and K ions stick to the external membrane
Result: a membrane voltage that is... quite null.

Osmosis:
Since there are concentrations changes there is water flux through aquaporins:
1/ from int to ext for sodium
2/ from ext to int for potassium
Result : How is it possible to make a bidirectional and simultaneous water movement in aquaporins?
 
  • #41
Let's take now the hypothesis where external membrane is covered by positive ions and internal one by negative ones.
The Na/K pump owns fantastic properties :
It takes out sodium while it pumps in potassium.
But... But...
It takes out sodium against a negative barrier. This negative barrier attracts positive ions.
It pumps in potassium against a positive barrier. This positive barrier reppels positive ions.
That's two major problems.

You will face to the same problems with the event of an action potential.
 
  • #42
http://en.wikipedia.org/wiki/Action_potential#Ion_pumps

Ion pumps influence the action potential only by establishing the relative ratio of intracellular and extracellular ion concentrations. The action potential involves mainly the opening and closing of ion channels, not ion pumps. If the ion pumps are turned off by removing their energy source, or by adding an inhibitor such as ouabain, the axon can still fire hundreds of thousands of action potentials before their amplitudes begin to decay significantly.[23] In particular, ion pumps play no significant role in the repolarization of the membrane after an action potential.[10]
 

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