How Does Friction Affect the Deceleration and Distance Traveled by a Motorboat?

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Homework Help Overview

The problem involves a motorboat that decelerates due to friction when its engine is turned off. The friction force is described by a specific equation, and the original poster seeks to determine the time it takes for the boat's speed to reduce to one-third of its initial value and the distance traveled during this time.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to formulate a differential equation based on the friction force but expresses uncertainty about the next steps. Another participant suggests a method for integrating the equation with specific boundaries. There is also a hint provided regarding the use of the chain rule to relate acceleration and velocity.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to solving the differential equation. Some guidance has been offered regarding integration techniques and the application of the chain rule, but there is no explicit consensus on the method to proceed or the final outcomes.

Contextual Notes

There are indications of potential confusion regarding the formulation of the friction force and the correct limits for integration, which may affect the problem setup.

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Homework Statement


When engine was turned off,boat with mass m was moving with speed v_0.
The force of friction F=-[itex]\alpha[/itex][itex]\nu[/itex]-[itex]\beta[/itex]v^2.
How long it would take to drop speed of boat 3 times?
Find the distance which the boat will travel in this time?


Homework Equations





The Attempt at a Solution


I think i should try to solve differental equation in form of
m[itex]\dot{v_0}[/itex]=-[itex]\alpha[/itex][itex]\nu[/itex]-[itex]\beta[/itex]v^2

But I really don't know what to do next,could someone,please help me with some steps or tips?


 
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Ok,now I am pretty sure that i have to solve DE :
[itex]\int(\frac{dv}{ \alpha v+\beta v^2})[/itex]=[itex]\int dt[/itex]

And integration bondaries from v=v_0 to v_0/3 ?
And for other intergral offcourse its fromt=0 to t_0

Either way, how can I find the distance?

Please help .
 
Hint: Use
$$a = \frac{dv}{dt} = \frac{dv}{dx}\frac{dx}{dt} = v\frac{dv}{dx}.$$ This is just the chain rule.
 
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prehisto said:
Ok,now I am pretty sure that i have to solve DE :
[itex]\int(\frac{dv}{ \alpha v+\beta v^2})[/itex]=[itex]\int dt[/itex]

And integration bondaries from v=v_0 to v_0/3 ?
And for other integral of course its from t=0 to t_0
You dropped a minus sign (as well as a factor m). You could fix the sign by changing the v limits to being from v0/3 to v0.
I note that in the OP you gave the force as being ##-\alpha \nu -\beta v^2##. I assume you meant ##-\alpha v -\beta v^2##
 
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