How Does Friction Affect the Motion of Three Blocks?

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Homework Help Overview

The discussion revolves around a physics problem involving three blocks and the effects of friction on their motion. The problem specifically addresses the relationship between the masses, tensions, and frictional forces in a system where one block is affected by kinetic friction on a table.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the equations of motion for each block, particularly focusing on the application of Newton's second law. There are attempts to set up equations for the tensions and forces acting on the blocks, with some questioning the assumptions made about the tensions being equal.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance on how to approach the problem. There is recognition of the need to derive separate equations for each mass and to consider the differences in tension for the blocks. Multiple interpretations of the problem setup are being explored.

Contextual Notes

Participants are working under the constraints of the given coefficients of friction and the masses involved. There is an emphasis on ensuring the correct application of physical laws without providing direct solutions.

complexc25
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You are given that the coefficient of kinetic friction between the block and the table in the figure is 0.560, and m1 = 0.150 kg and m2 = 0.250 kg.
(a) What should m3 be if the system is to move with a constant speed?

this is what i have:
T2 - T1 - f = m3a

m2g - m1g - ukg = m3
2.45 - 9.65 - 5.488 = 4.508kg

the answer is wrong, what is it that i am doing wrong?
 

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complexc25 said:
this is what i have:
T2 - T1 - f = m3a
This is good.

m2g - m1g - ukg = m3
2.45 - 9.65 - 5.488 = 4.508kg
This is not good. For one thing, the tensions are not equal to the weights.

Hint: Apply Newton's 2nd law to each mass separately. You took care of M3, now come up with equations for M1 & M2.

You'll combine all three equations to solve for the acceleration and the tensions.
 
i don't understand, i have for:
m1
T - m1g = m1a
m2
m2g - T = m2a
 
complexc25 said:
i don't understand, i have for:
m1
T - m1g = m1a
m2
m2g - T = m2a
Looks good, except that the tensions are different. Use T1 for m1 and T2 for m2.
 

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