How Does Light Refraction Affect Displacement in a Glass Medium?

Click For Summary

Homework Help Overview

The discussion revolves around the effects of light refraction in a glass medium, specifically focusing on the displacement of a light ray as it passes through a glass with a given refractive index and thickness. The original poster presents a formula related to this displacement and seeks assistance in deriving it using trigonometric principles.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the angles of incidence and refraction, and the geometry involved in the displacement of the light ray. There are attempts to connect trigonometric concepts to the problem, with some participants suggesting the importance of drawing a diagram to visualize the situation.

Discussion Status

Some participants have confirmed that they have drawn diagrams, which has helped clarify their understanding of the problem. However, there remains a struggle to connect the trigonometric relationships to the formula in question, indicating that the discussion is still in a developmental phase without a clear resolution.

Contextual Notes

Participants are working under the assumption that the incident and final refracted rays are parallel, which is a key aspect of the problem. There is also a mention of the original poster's difficulty in applying trigonometric principles to derive the formula.

Pixter
Messages
29
Reaction score
0
Okej have a piece of glass with refractive index n2 and tickness t.

A ray of light falls on the glass with the angle theta1 (from a medium with recrative index n1).

In the glass the ray has the angle theta2 and when it exits it has now got the displacement d (compared with the ray that went from air to glass).

Now show that the formula d=tsin(theta1)(1-(n1cos(theta1) / n2cos(theta2)) is correct.

I know it is suppose to be simple trig, but the only thing i can even figure out to do is that 90-theta1 = theta ... then I'm stuck.. can't see how to connect anything. please give me some hints.
 
Last edited:
Physics news on Phys.org
Have you drawn a diagram? Hint: the incident ray and the the final refracted ray should be parallel.
 
Hootenanny said:
Have you drawn a diagram? Hint: the incident ray and the the final refracted ray should be parallel.

yeah they are parallel of course.. but just finding the displacement of them..

have done a diagram as well. but as I said I can't figure out what to start with. can't see the trig stuff in it =(
 
Hootenanny said:
Have you drawn a diagram? Hint: the incident ray and the the final refracted ray should be parallel.
Oki done it know.. and it made perfect sense..=)
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 3 ·
Replies
3
Views
11K
  • · Replies 4 ·
Replies
4
Views
3K